The example on direct variation is illustrated below based on the information given.
<h3>How to illustrate the direct variation?</h3>
An example will be:
When x = 2, y = 10. Find the value of y when x is 6.
In this case, this will be calculated thus:
y = kx
10 = 2k
k = 10/2
k = 5
Since y = kx.
y = 5 × 6
y = 30
The value of y is 30.
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Your answer is (z+1+w) (z+1-w)
Answer:
9
Step-by-step explanation:
x didn't change in value, y changed by 9
the distance between the two points is 9
Answer:
(x, y) = (- 3, 4)
Step-by-step explanation:
Given the 2 equations
5x + 2y = - 7 → (1)
4x - y = - 16 → (2)
multiply all terms in (2) by 2
8x - 2y = - 32 → (3)
Add (1) and (3) term by term
(5x + 8x) + (2y - 2y) = (- 7 - 32)
13x = - 39 ( divide both sides by 13 )
x = - 3
Substitute x = - 3 into either (1) or (2) and solve for y
substituting in (1) gives
(5 × - 3) + 2y = - 7
- 15 + 2y = - 7 ( add 15 to both sides )
2y = 8 ( divide both sides by 2 )
y = 4
solution is (- 3, 4 )