Answer:
Proved
Step-by-step explanation:
To Prove: 
Proof:
Now: 
Therefore:

Applying these angle sum formula


Divide all through by 

=sin \alpha cos \beta + cos \alpha sin \beta/cos \alpha cos \beta/cos \alpha cos \beta- sin \alpha sin \beta/cos \alpha cos \beta
=sin \alpha/cos \alpha + sin \beta/cos \beta/1-tan \alpha tan \beta
=tan A + tan B/1-tan A tan B
It is a parallelogram because the opposite sides, 100 and 80, add up to 180.
Answer:
Given, length, l = 3/8 inches
breadth, b =2/3 inches
We have
area = l × b
= 3/8 × 2/3
= 6/24
To find out how much more volume Max's carton has when compared to Tucker's, you will need to find the volume of each and then compare them.
Max:
V = BH, where B is the base area
= 12 in^2 x 6 in
V = 72 cubic inches
Tucker:
V = BH
= 10 in^2 x 7 in
V = 70 cubic inches
Max's carton is 72 cubic inches and Tucker's carton is 70 cubic inches. Max's is 2 cubic inches greater.