I'm guessing it's like this
example
18=2*3*3=(2¹)(3²)
315/5=63
63/3=21
21/3=7
factored form is 3*3*5*7=(3²)(5¹)(7¹)
Answer:
<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>
Step-by-step explanation:
Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.
We know that, 
So, the <u>speed of Pratap with the current</u> will be:
miles/hour
and the <u>speed of Pratap against the current</u> will be:
miles/hour.
Suppose, the rate of Pratap in still water is
and the rate of current is
.
So, the equations will be........

Adding equation (1) and (2) , we will get......

Now, plugging this
into equation (1), we will get.....

Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.
Answer:
C.
Step-by-step explanation:
Simply multiply 50 by 3/8
You're correct, the answer is C.
Given any function of the form

, then the derivative of y with respect to x (

) is written as:

In which

is any constant, this is called the power rule for differentiation.
For this example we have

, first lets get rid of the quotient and write the expression in the form

:

Now we can directly apply the rule stated at the beginning (in which

):

Note that whenever we differentiate a function, we simply "ignore" the constants (we take them out of the derivative).