I found this since im really bad at explaining
Answer:
Step-by-step explanation:
Given is a Laplace transform of f(t) as
Let
Solving we get 
Solving B=0=D
Hence we have
f(t) = inverse Laplace of
![\frac{1}{7}[ \frac{s}{(s^2+9)}-\frac{s}{(s^2+16)}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B7%7D%5B%20%5Cfrac%7Bs%7D%7B%28s%5E2%2B9%29%7D-%5Cfrac%7Bs%7D%7B%28s%5E2%2B16%29%7D%5D)
=
Answer:
A=4, B=3, C=2, D=7 or A=2, B=7, C=4, D=3
Step-by-step explanation:
To factor this, you are looking for factors of 8×21 = 168 that have a sum of 34.
168 = 1×168 = 2×84 = 3×56 = 4×42 = 6×28 = 7×24 = 8×21 = 12×14
The sums of these factor pairs are 169, 86, 59, 46, 34, 31, 29, 26. The factor pair whose sum is 34 is 6×28. This means we can rewrite the expression as ...
8x² +28x +6x +21
Factoring by pairs gives ...
4x(2x +7) +3(2x +7)
(4x +3)(2x +7) ⇒ A=4, B=3, C=2, D=7 or A=2, B=7, C=4, D=3
(a)^1/3
------------ = (a)^1/3-1/4 = (a)^1/12
(a)^1/4
