Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.
We are to find the probability of selecting 1 red apple and 2 yellow apples.
Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.
Then, we have

Therefore, the probability of event A is given by

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Area = 256*3.14=804feet^2
Answer:

Step-by-step explanation:
8x+9=0
8x=-9

or

,



, 
Answer:
a) 6/9 shaded.
b) About 67% is shaded. (66.6% repeating rounded to 67%)
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