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just olya [345]

2 years ago

5

James rode k kilometers on his bike this week. Express the number of kilometers that Ivan rode on his bike in terms of k if he r

ode 3 kilometers less tha times the number of kilometers that James rode,

1 answer:

Amiraneli [1.4K]2 years ago

4 0

Answer:

13 km/hr

Step-by-step explanation:

Speed = (distance covered) / (time to cover the distance)

( 8.45 km) / (0.65 hr)

(8.45 / 0.65) km/hr

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Round 813,764 to the nearest Ten Thousand.<br> A-820,000<br> B-814,000<br> C-810,00<br> B-813,000

kkurt [141]

Answer:

C - 810,000

Step-by-step explanation:

The ten-thousandths place in 813,764 is the 1

Since the 3 (after the 1) is less than 5, round down

Rounding gives you 810,000

3 0

2 years ago

Which sequence is modeled by the graph below? coordinate plane showing the points 1, 1; 2, 2; 3, 4; and 4, 8

abruzzese [7]

The points of the graph are> (1,1), (2,2), (3,4), (4,8).

Then the sequence is:

- for the x-coordinate: 1, 2, 3, 4, 5, 6, 7, ...

- for the y-coordinate: 1, 2, 4, 8, which is: 2^0, 2^1, 2^2, 2^ 3, ... so the next y-coordinates are 16, 32, 64, 128, ...

So, the sequence is: 1, 2, 4, ,8, 16, 32, .... 2^x.

5 0

3 years ago

10. Create a scenario to explain why 3P3=3!.

Flauer [41]

Step-by-step explanation:

Permutation :The number of ways to choose a sample of r elements from a set of n distinct objects where order does matter and replacements are not allowed.

$nPr = \frac{n!}{(n-r)!}$

Factorial : There are n! ways of arranging n distinct objects into an ordered sequence.

Considering a situation when n = r in a permutation, nPr reduces to n!, a simple factorial of n.

Proof: 3P3 = 3!

n = 3 and r = 3

$3P3 = \frac{3!}{(3-3)!}$

$3P3 = \frac{3!}{(0)!}$

But 0! = 1

3P3 = 3!

3 0

3 years ago

Read 2 more answers

Resolver la siguiente ecuación por eliminación o sustitución: a-8b= -9 a-2b= -7

Crazy boy [7]

Answer: Solution: $a=\dfrac{-19}{3}$ and $b=\dfrac{1}{3}$ .

Step-by-step explanation:

The given pair of equations:

$a-8b= -9\ ...(i)\\\\ a-2b= -7\ ...(ii)$

Eliminate equation (i) from (ii) , we get

$-2b-(-8b)=-7-(-9)\\\\\Rightarrow\ -2b+8b=-7+9\\\\\Rightarrow\ 6b=2\\\\\Rightarrow\ b=\dfrac{1}{3}$

Put value of b in (ii) , we get

$a-2\times\dfrac{1}{3}=-7\\\\\Rightarrow\ a=-7+\dfrac{2}{3}\\\\\Rightarrow\ a=\dfrac{-21+2}{3}\\\\\Rightarrow\ a=\dfrac{-19}{3}$

Solution: $a=\dfrac{-19}{3}$ and $b=\dfrac{1}{3}$ .

4 0

3 years ago

Can someone help please?

deff fn [24]

Slope = 75
Y-intercept = 150

8 0

3 years ago