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amid [387]
3 years ago
15

Difference of two squares Calculate this 81-(3x-2)^2 ^2= to the power of 2

Mathematics
1 answer:
Marat540 [252]3 years ago
5 0
<span>81-(3x-2)^2
= </span><span>81-(-6)^2
= 81 - 36
= 45

hope it helps</span>
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\huge\mathfrak\green{answer}

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\red{multiply}

= q -  \frac{cq7}{10} =  \frac{41}{5}

\red{subtract \: q \: from \: both \: sides}

= q -  \frac{cq7}{10}  - q =  \frac{41}{5} - q

\red{now \: simplify}

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\red{multiply \: 10 \: both \: sides}

= 10( -  \frac{cq7}{10} ) = 10. \frac{41}{5}  - 10q

\red{simplify}

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\red{now \: divide}

=  \frac{ - cq7}{ - q7}  -  \frac{82}{ - q7}  -  \frac{10q}{ - q7}

\red{simplify}

= c =   - \frac{82 - 10q}{q7} (q≠0)

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\huge\mathfrak\green{thank \: you}

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