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kap26 [50]
3 years ago
10

Can anyone tell me the area? I will give brainlist if I'm able to​

Mathematics
1 answer:
pantera1 [17]3 years ago
3 0

Answer:

143 yds^2

Step-by-step explanation:

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Write -3x^2-18-31 in vertex form.
chubhunter [2.5K]
Get into form a(x-h)²+k

complete the square

-3x²-18x-31
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(-3x²-18x)-31
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take 1/2 of the linear coefient (6) and squaer it
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3 years ago
Simplify the expression: 2√75+ √20
xxTIMURxx [149]

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Step-by-step explanation:

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How do you factor a polynomial when one root has been given
zloy xaker [14]
So first what you are going to do is divide synthetically your root aka factor into your given equation. Then you are going to kind of guess ands check to find the other factor by synthetically dividing what you have left which should be
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7 0
4 years ago
Read 2 more answers
As part of a screening process, computer chips must be operated in an oven at 145 °C. Ten minutes after starting, the temperatur
Novosadov [1.4K]

Answer:

Step-by-step explanation:

I solved this using initial conditions and calculus, so I hope that's what you are doing in math.  It's actually NOT calculus, just a concept that is taught in calculus.

The initial condition formula we need is

y=Ce^{kt}

Filling in our formula with the 2 conditions we are given:

65=Ce^{10k}   and   85=Ce^{15k}

With those 2 equations, we have 2 unknowns, the C (initial value) and the k (the constant). We know that the initial value (or starting temp) for both conditions is the same, so we solve for C in one equation, sub it into the other equation and solve for k.  If

65=Ce^{10k} then

\frac{65}{e^{10k}}=C which, by exponential rules is the same as

C=65e^{-10k}

Since that value of C is the same as the value of C in the other equation, we sub it in:

85=65e^{-10k}(e^{15k})

Divide both sides by 65 and use the rules of exponents again to get

\frac{85}{65}=e^{-10k+15k} which simplifies down to

\frac{85}{65}=e^{5k}

Take the natural log of both sides to get

ln(\frac{85}{65})=5k

Do the log thing on your calculator to get

.2682639866 = 5k and divide both sides by 5 to find k:

k = .0536527973

Now that we have k, we sub THAT value in to one of the original equations to find C:

65=Ce^{10(.0536527973)}

which simplifies down to

65=Ce^{.536527973}

Raise e to that power on your calculator to get

65 = C(1.710059171) and divide to solve for C:

C = 38.01038064

Now sub in k and C to the final problem when t = 23:

y=38.01038064e^{(.0536527973)(23)} which simplifies a bit to

y=38.01038064e^{1.234014338}

Raise e to that power on your calculator to get

y = 38.01038064(3.434991111) and

finally, the temp at 23 minutes is

130.565

6 0
3 years ago
What is the value of the expression
Y_Kistochka [10]

Answer:

0.8

Step-by-step explanation:

We begin with the expression: 0.5+(-\frac{3}{4} )+0.25-(-\frac{4}{5} )

First, we need to convert the fractions into decimals to make this easier.

-\frac{3}{4}=-0.75 and -\frac{4}{5} =-0.8

Once we have this, we can simplify it

0.5-0.75+0.25-(-0.8)\\\\0.5-0.75+0.25+0.8\\\\0.75-0.75+0.8\\\\0.8

4 0
4 years ago
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