What is the first step needed to solve (1)x-3=-18?

Jina needs to memorize words on a vocabulary list for German class. She has memorized 30 of the words, which is one-third of the

hjlf

I belive it is 90 hope ihelped

5 0

4 years ago

Using the quadratic formula, which of the following are the zeros of the

ale4655 [162]

Answer:

I think it's C but I'm not 100%

8 0

3 years ago

Read 2 more answers

Which three lengths could be the lengths

Fed [463]

Given:

The three lengths in the options.

To find:

Which three lengths could be the lengths of the sides of a triangle?

Solution:

If the sum of two smaller sides is greater than the largest side, then the three sides can form a triangle otherwise the triangle is not possible.

In option A, the three sides are 4 cm, 8 cm, 13 cm. Here, the largest side is 13 cm.

Sum of two smaller sides is:

$4+8=12$

$4+8$

So, the triangle is not possible.

In option B, the three sides are 13 cm, 11 cm, 23 cm. Here, the largest side is 23 cm.

Sum of two smaller sides is:

$13+11=24$

$13+11>23$

So, the triangle is possible.

In option C, the three sides are 5 cm, 18 cm, 12 cm. Here, the largest side is 18 cm.

Sum of two smaller sides is:

$5+12=17$

$5+12$

So, the triangle is not possible.

In option D, the three sides are 25 cm, 8 cm, 16 cm. Here, the largest side is 25 cm.

Sum of two smaller sides is:

$8+16=24$

$8+16$

So, the triangle is not possible.

Therefore, the correct option is B. The three lengths 13 cm, 11 cm, 23 cm could be the lengths of the sides of a triangle.

6 0

3 years ago

(1 point) The effectiveness of a new bug repellent is tested on 18 subjects for a 10 hour period. Based on the number and locati

jolli1 [7]

Answer:

z=1.59

If we compare the p value and the significance level given $\alpha=0.025$ we see that $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, so we can conclude that the mean repellency of the new bug repellent is greater than 89% at 0.025 of signficance.

Step-by-step explanation:

1) Data given and notation

$\bar X=0.92$ represent the mean effectiveness of a new bug repellent for the sample

$\sigma=0.08$ represent the population standard deviation for the sample

$n=18$ sample size

$\mu_o =0.89$ represent the value that we want to test

$\alpha=0.025$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean repellency of the new bug repellent is greater than 89% or 0.89, the system of hypothesis would be:

Null hypothesis: $\mu \leq 0.89$

Alternative hypothesis: $\mu > 0.89$

We don't know the population deviation, and the sample size <30, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{0.92-0.89}{\frac{0.08}{\sqrt{18}}}=1.59$

Calculate the P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=18-1=17$

Since is a one-side upper test the p value would be:

$p_v =P(t_{17}>1.59)=0.065$

In Excel we can use the following formula to find the p value "=1-T.DIST(1.59;17;TRUE)"

Conclusion

If we compare the p value and the significance level given $\alpha=0.025$ we see that $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, so we can conclude that the mean repellency of the new bug repellent is greater than 89% at 0.025 of signficance.

6 0

4 years ago

I need help please.

pshichka [43]

Answer:

e

Step-by-step explanation:

3 0

3 years ago