Answer:
P____Q____R
PR= PQ+ QR
(14x-13) = (5x-2)+(6x+1)
14x-13= 11x – 1
14x – 11x = 13–1
3x = 12
x= 12/ 3
x= 4
PR= 14x – 13 = 14 (4) – 13 = 18 – 13= 5
If you want (PQ , QR ) this is the solution
PQ =5x-2=5(4)-2=20-2=18
QR =6x+1=6(4)+1=24+1=25
I hope I helped you^_^
4. 8
/ \ / \
2 x 2. 4 x 2
/ \
2 x 2
4: 2x2
8: 2x2x2
The GCF is 4
Difference of two squares is of the form (a + b)(a - b) or vice-versa. Here, a = -5x and b = 3.
(-5x - 3)(-5x + 3)
Answer: 3
Answer:
The equations represent circles that result in the same graph.
Step-by-step explanation:
we have

Divide by -10 both sides
-----> equation A
This is the equation of a circle centered at origin with radius 
and
Divide by 5 both sides
-----> equation B
This is the equation of a circle centered at origin with radius 
equation A and equation B are equal
therefore
The system has infinite solutions, because the equations represent circles that result in the same graph.
Answer:
don't under stand your question please