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NeTakaya
3 years ago
8

Consider the equations: y = 2x − 2 and y = 3x − 2.

Mathematics
2 answers:
Amanda [17]3 years ago
8 0

Answer:

The ordered pair (0, 2) satisfies both equations.

The correct answer is A (0, 2).

Step-by-step explanation:

I just did the Usatestprep.

Stells [14]3 years ago
3 0

Answer:

Letter C is your answer.

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A 2-column table with 5 rows. The first column, number of snapdragons, x, has the entries 11, 12, 13, 14. The second column, num
mamaluj [8]

9514 1404 393

Answer:

  16

Step-by-step explanation:

The values in each row of the table have a total of 45. If Hans plants 29 daisies, he likely will plant ...

  45 -29 = 16 . . . snapdragons

__

One can also find the answer by extending the table 2 more rows. Each x entry increases by 1 as each y entry decreases by 1. Then the number of snapdragons listed in the second added row will be 14+2 = 16.

3 0
3 years ago
Read 2 more answers
First one to Answer it correctly gets 5 stars :)
faust18 [17]

Answer:

im not the best but i think 200 or 400 m

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Ill mzrkb brainlist plss help
Anvisha [2.4K]

Answer:

i think 41.3

Step-by-step explanation:

6 0
3 years ago
Round 104229 to the nearest ten thousand
saul85 [17]
That is a one hundred thousand number. To round it you need to know this: 5 or more make it go up (make it the next number. For example: 19,530. It would be rounded to 20,000 because of the 5) 4 or less let it be (EXAMPLE : 8,213. It would be 8,000. Because of the 4.) 

Then you need to find the ten thousand. In this case it is the 0. (104,229) Then you round it off to 100,000. The answer is 100,000.
3 0
4 years ago
How do you solve these problems?
Rzqust [24]
A)

\bf log_4(x)=3\\\\
-----------------------------\\\\
log_{{  a}}{{  a}}^x\implies x\qquad \qquad 
\boxed{{{  a}}^{log_{{  a}}x}=x}\impliedby 
\begin{array}{llll}
\textit{we'll use this}\\
\textit{cancellation rule}
\end{array}\\\\
-----------------------------\\\\
4^{\cfrac{}{}log_4(x)}=4^3\implies x=4^3

b)

\bf 3^{2y}=81\qquad 
\begin{cases}
81=3\cdot 3\cdot 3\cdot 3\\
\qquad 3^4
\end{cases}\implies 3^{2y}=3^4\impliedby 
\begin{array}{llll}
\textit{same base}\\
exponents\\
must\ be\\
the\ same
\end{array}
\\\\\\
2y=4\implies y=\cfrac{4}{2}\implies y=2
6 0
4 years ago
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