You add all the numbers & divide it by how many numbers 8 +9+9+9+10+10
Answer:
Rx)=1/3x^2
Step-by-step explanation:
A horizontal stretch is simply making the parabola of the parent function wider, it's kind of like changing the slope of a line to make it less steep.
In the graph, the red line is the parent function and the blue line is the horizontally stretched function. See how the blue line appears to be stretched (horizontally).
Answer:
8 chicken and 4 beeff
Step-by-step explanation:
The center is (-1, -2) and the radius of the circle is 5.
<h3>What is the equation of a circle?</h3>
The circle equation formula refers to the equation of a circle which represents the center-radius form of the circle.
A circle can be represented as;
Where; h and k are the center of the circle r is the radius of the circle.
The given equation of the circle is;
Comparing both the equations;
Hence, the center is (-1, -2) and the radius of the circle is 5.
Learn more about circle here;
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Answer: B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
Step-by-step explanation:
Here are the options:
A There are more boys at Mark's school than at Leslie's school because the ratio 11 to 12 is greater than the ratio 41 to 48.
B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
C. There are more boys at Leslie's school than at Mark's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
At leslie's school the ratio of boys and girls is 11 to 12. This implies that the fraction of boys in the school to total students will be:
= 11/(11 + 12) = 11/23 = 0.4783
At Marks school the ratio of boys to girls is 41 to 48. Thus implies that the fraction of boys in the school to total students will be:
= 41 / (41 + 48) = 41/85= 0.4824
Based on the calculation, we can deduce that there are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.