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3 years ago

If $6500 is invested at a rate of 6% compounded continuously, find the balance in the account after 3 years

1 answer:

6 0

$\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6500\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ t=years\dotfill &3 \end{cases} \\\\\\ A=6500e^{0.06\cdot 3}\implies A=6500e^{0.18}\implies A\approx 7781.91$

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sarita used 54 oz. of apples to make an apple pie. how many pounds and ounces of apples did sarita use?

sergejj [24]

The highest we can go is 48 oz
3 lbs is 48 oz
54-48= 6
So the answer is
Answer: 3 lbs and 6 oz

Hope i helped <3

5 0

3 years ago

ASAP The rectangle below has been enlarged by a scale of 3.5. A rectangle with a length of 8 and width of 6. [Not drawn to scale

Sergeu [11.5K]

Answer:

588 units^2

Step-by-step explanation:

To find the area of the enlarged rectangle, first find the length and width of the enlarged rectangle.

This is 3.5 multiplied by their original measures:

Length = 3.5 x 8 = 28

Width = 3.5 x 6 = 21

Now, area =. LxW = 588 units^2

Hope this helps

5 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

2 years ago

Look at the screenshot

kirza4 [7]

Answer:

The answer is d and b hope this helps!

3 0

2 years ago

Read 2 more answers

Write the word sentence as an inequality.

garik1379 [7]

Answer:

-5b <= -34

Step-by-step explanation:

The inequality phrase, "at most" is same as "less than or equal to". So the algebraic inequality would be -5b <= -34. To solve for b, divide both sides by -5 and make sure to switch the inequality symbol to >= when dividing or multiplying inequalities by a negative number. So b >= 34 / 5.

4 0

2 years ago