Question

What are the zeros of the quadratic function f(x)=2x^2+8x-3

Answer 1

Answer:

-2 +/-  [(sqrt 88)/ 4]

or

0.35, -4.35 to the nearest hundredth.

Step-by-step explanation:

2x^2 + 8x - 3 = 0

Using the quadratic formula:

x = [ -8 +/- sqrt (8^2 - 4*2*-3) ] / 4

=  -2 +/-  (sqrt 88)/ 4