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evablogger [386]
3 years ago
10

What are the zeros of the quadratic function f(x)=2x^2+8x-3

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
8 0

Answer:

-2 +/-  [(sqrt 88)/ 4]

or

0.35, -4.35 to the nearest hundredth.

Step-by-step explanation:

2x^2 + 8x - 3 = 0

Using the quadratic formula:

x = [ -8 +/- sqrt (8^2 - 4*2*-3) ] / 4

=  -2 +/-  (sqrt 88)/ 4

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Now solve it by applying

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3 years ago
A cell tower is located at and transmits a circular signal that covers three major cities. The three cities are located on the c
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Answer:

(x+8)^2 +(y-4)^2 = 25

Step-by-step explanation:

Assuming this complete problem: "A cell tower is located at (-8, 4) and transmits a circular signal that covers three major cities. The three cities are located on the circle and have the following coordinates: G (-4, 7), H (-13, 4), and I (-8, -1). Find the equation of the circle"

For this case the generla equation for the circle is given by:

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From the info we know that the tower is located at (-8, 4) so then h = -8 and k = 4, so then we need to find the radius. So we have the equation like this:(x+8)^2 +(y-4)^2 = r^2

If the 3 points are on the circle then satisfy the equation. We can use the first point (-4,7) and if we replace we can find the value for r^2

(-4+8)^2 +(7-4)^2 =25= r^2

So then r = \sqrt{25}=5

And if we replace the second point we got this:

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And for the third point we have:

(-8+8)^2 +(-1-4)^2 = 25 =r^2

And we got the same result.

So then our final equation is given:

(x+8)^2 +(y-4)^2 = 25

4 0
4 years ago
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i think 64?

Step-by-step explanation:

its supposed to be the same on the bottom, right?

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