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evablogger [386]
3 years ago
10

What are the zeros of the quadratic function f(x)=2x^2+8x-3

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
8 0

Answer:

-2 +/-  [(sqrt 88)/ 4]

or

0.35, -4.35 to the nearest hundredth.

Step-by-step explanation:

2x^2 + 8x - 3 = 0

Using the quadratic formula:

x = [ -8 +/- sqrt (8^2 - 4*2*-3) ] / 4

=  -2 +/-  (sqrt 88)/ 4

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AveGali [126]
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(27^(1/3))^2  the cube root of 27=±3

(±3)^2  and ±3^2=9

So the equivalent expression is 9  or if you need an exponent 9^1 :)

I am assuming that you meant 27^(2/3)
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3 years ago
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g100num [7]

Given:

The algebra tiles of an equation.

To find:

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