What are the zeros of the quadratic function f(x)=2x^2+8x-3
1 answer:
Answer:
-2 +/- [(sqrt 88)/ 4]
or
0.35, -4.35 to the nearest hundredth.
Step-by-step explanation:
2x^2 + 8x - 3 = 0
Using the quadratic formula:
x = [ -8 +/- sqrt (8^2 - 4*2*-3) ] / 4
= -2 +/- (sqrt 88)/ 4
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LHS = RHS
(5 - 3) x A = -128
( 2 ) x A = -128
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A = -64
The answer is x = 6
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3%
Step-by-step explanation:
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Step-by-step explanation:
