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2 years ago

Two equations are shown in the picture please answer. giving brainiest

Mathematics

1 answer:

Dvinal [7]2 years ago

6 0

Answer:well for the first one I am not sure but I think that since four is over the x there should be 4/x + 3 so tragically I don’t know the answer but I think it should be 12 the x should be 12 because 4x3=12 so yea 12

Step-by-step explanation:and for the other one I don’t know but ima try it should be two because 2x2=4 and so y=1-2x2-4 that’s what I think sorry. I got it wrong and do good on your test for me please

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Inequalities Which is the graph of the system x + 3y > -3 and y < 1/2x +1?

OLga [1]

Answer:

the 4th graph.

Step-by-step explanation:

by solving for Y in the first equation, we get the y-intercept of -1 and the second equation has a y-intercept of 1. 4th graph is the only graph with those 2 intercepts

6 0

2 years ago

Find the quotient of 812.30 divided by 83. Round to the nearest tenth.

elena-14-01-66 [18.8K]

812.30/83 = 9.78674698.....
Nearest tenth means one number under decimal place so...

812.30/83 ~ 9.8

Explanation: The 9.7... rounded up to 9.8 because the number after the tenths place (in this case the number after the 7) is greater or equal to 5.

7 0

3 years ago

Victor was having a hard time deciding which new vehicle he should buy. He decided to make the final decision based on the gas e

Amanda [17]

Answer:

Victor should buy Legend because it has a better unit rate

Step-by-step explanation:

See attachment for complete question.

To determine which car has more gas efficiency, we have to calculate the slope of each car.

Vehicle 1: Legend

Take any two corresponding points from the table

$(x_1,y_1) = (4,72)$

$(x_2,y_2) = (12,216)$

The slope is then calculated using;

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{216 - 72}{12 - 4}$

$m = \frac{144}{8}$

$m = 18$

This implies that this vehicle (legend) travels 18 miles per gallon of gas

Vehicle 2: Supreme

Take any two corresponding points from the graph

$(x_1,y_1) = (0,0)$

$(x_2,y_2) = (15,250)$

The slope is then calculated using;

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{250 - 0}{15 - 0}$

$m = \frac{250}{15}$

$m = 16.7$

This implies that this vehicle (supreme) travels 16.7 miles per gallon of gas

Base on the calculations above, Victor should buy Legend because it has a better unit rate

6 0

2 years ago

The maximum weight for a truck in Oregon without a special permit is 40 tons what is the greatest number of pounds what is the g

Nimfa-mama [501]

Answer:

80,000lbs

Step-by-step explanation:

40 tons = 80000lbs

8 0

2 years ago

A student is getting ready to take an important oral examination and is concerned about the possibility of having an "on" day or

Tamiku [17]

Answer:

The students should request an examination with 5 examiners.

Step-by-step explanation:

Let X denote the event that the student has an “on” day, and let Y denote the

denote the event that he passes the examination. Then,

$P(Y)=P(Y|X)P(X)+P(Y|X^{c})P(X^{c})$

The events ( $Y|X$ ) follows a Binomial distribution with probability of success 0.80 and the events ( $Y|X^{c}$ ) follows a Binomial distribution with probability of success 0.40.

It is provided that the student believes that he is twice as likely to have an off day as he is to have an on day. Then,

$P(X)=2\cdot P(X^{c})$

Then,

$P(X)+P(X^{c})=1$

⇒

$2P(X^{c})+P(X^{c})=1\\\\3P(X^{c})=1\\\\P(X^{c})=\frac{1}{3}$

Then,

$P(X)=1-P(X^{c})\\=1-\frac{1}{3}\\=\frac{2}{3}$

Compute the probability that the students passes if request an examination with 3 examiners as follows:

$P(Y)=P(Y|X)P(X)+P(Y|X^{c})P(X^{c})$

$=[\sum\limits^{3}_{x=2}{{3\choose x}(0.80)^{x}(1-0.80)^{3-x}}]\times\frac{2}{3}+[\sum\limits^{3}_{x=2}{{3\choose x}(0.40)^{3}(1-0.40)^{3-x}}]\times\frac{1}{3}$

$=0.715$

The probability that the students passes if request an examination with 3 examiners is 0.715.

Compute the probability that the students passes if request an examination with 5 examiners as follows:

$P(Y)=P(Y|X)P(X)+P(Y|X^{c})P(X^{c})$

$=[\sum\limits^{5}_{x=3}{{5\choose x}(0.80)^{x}(1-0.80)^{5-x}}]\times\frac{2}{3}+[\sum\limits^{5}_{x=3}{{5\choose x}(0.40)^{x}(1-0.40)^{5-x}}]\times\frac{1}{3}$

$=0.734$

The probability that the students passes if request an examination with 5 examiners is 0.734.

As the probability of passing is more in case of 5 examiners, the students should request an examination with 5 examiners.

8 0

2 years ago