12,000×(1+0.12÷2)^(2×6)+50,000×(1+0.12÷2)^(2×2)=87,270.21
Divide 22 by 2 to get "c" isolated.
53×2=106
2×53=106
106×1=106
1×106=106
The numbers that would be smaller would be the two with the difference of 26.
27-1=26 where as, if you were to use a 1 in each, 99+1= 100. Therefore 27 and 1 (28) is less than 99 and 1 (100).
The answer would be B because it crosses the X axis closer to the 0,0 than the original line
