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3 years ago

Help please !!!!! plz

Mathematics

1 answer:

Agata [3.3K]3 years ago

6 0

Centre of enlargement: (-12, 14)
Scale factor: 2

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PLEASE HELP! I. NEED. HELP. ASAP

kotykmax [81]

Just do 30%x179,000 and that will be the answer the equation is V (for value) V=53,700t

8 0

3 years ago

Someone please help and show work

aleksklad [387]

Answer:

a) 4 $x^{6}$

b) 2 $w^{4}$

Step-by-step explanation:

a) multiply the coefficients and add the exponents

(4)(1) · $x^{3+3}$ = 4 $x^{6}$

b) divide the coefficients and subtract the exponents

(14 ÷ 7) · $w^{6-2}$ = 2 $w^{4}$

4 0

3 years ago

What is the solution of the inequality Y+1<6

umka2103 [35]

Answer:

y < 5

Step-by-step explanation:

Given

y + 1 < 6 ( isolate y on the left side by subtracting 1 from both sides )

y < 5

6 0

3 years ago

Read 2 more answers

Whats the square root of 1/5 minus the square root of 5

I am Lyosha [343]

You have to simplify the 1/5 first.
Then simplify the square root of 1 to equal 1
Then rationalize the denominator
Then simplify

8 0

3 years ago

What is m∠C?<br><br> Round the value to the nearest degree.

Elis [28]

Answer: $m\angle C=53\°$

Step-by-step explanation:

For this exercise you need to use the Inverse Trigonometric function arcsine, which is defined as the inverse function of the sine.

Then, to find an angle α, this is:

$\alpha =arcsin(\frac{opposite}{hypotenuse})$

In this case, you can identify that:

$\alpha =m\angle C\\\\opposite=AB=36\ cm\\\\hypotenuse=AC=45\ cm$

Then, substituting values into $\alpha =arcsin(\frac{opposite}{hypotenuse})$ and evaluating, you get that the measure of the angle "C" to the nearest degree, is:

$m\angle C=arcsin(\frac{36\ cm}{45\ cm})\\\\m\angle C=53\°$

5 0

3 years ago