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nekit [7.7K]
3 years ago
13

I need help with my math homework is due tomorrow

Mathematics
1 answer:
love history [14]3 years ago
3 0
I am pretty sure number 12 is H.
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Rewrite an equation so does not have fractions 5/6x+2=3/6
Dovator [93]

9514 1404 393

Answer:

  5x +12 = 3

Step-by-step explanation:

Multiply both sides of the equation by the least common denominator. Here, that is 6.

  \dfrac{5}{6}x+2=\dfrac{3}{6}\qquad\text{given}\\\\6\left(\dfrac{5}{6}x+2\right)=6\times\dfrac{3}{6}\qquad\text{multiply by 6}\\\\5x+6\times2=3\qquad\text{eliminate parentheses}\\\\\boxed{5x+12=3}}

6 0
3 years ago
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Round 1.9541 to the nearest tenth
Karolina [17]

Answer:

2

Step-by-step explanation:

1.95 rounds up to 2 because the 5 rounds 9 up to 10, which is equivalent to 1.0 in this case, and that makes the answer 2.

3 0
3 years ago
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A rectangle has an area of 216.24 cm2 and a height of 15.9 cm. How long is the base of the rectangle ?
Helga [31]
The formula for the area of a rectangle is A = bh.
Substitute 216.24 for A (area) and 15.9 for h (height).

A = bh
216.24 = b(15.9)
÷ 15.9      ÷ 15.9            Divide 15.9 on both sides.
13.6 = b

So, the base of the rectangle is 13.6 cm.
5 0
3 years ago
In a certain Algebra 2 class of 29 students, 7 of them play basketball and 14 of them
Mariulka [41]

Answer:

<em>Two possible answers below</em>

Step-by-step explanation:

<u>Probability and Sets</u>

We are given two sets: Students that play basketball and students that play baseball.

It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.

This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

\displaystyle P=\frac{19}{29}

P = 0.66

Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:

We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.

Thus, there 19-2=17 students who play only one of the sports. The probability is:

\displaystyle P=\frac{17}{29}

P = 0.59

3 0
3 years ago
HELP DUE IN 10 MINS!<br><br> Attached is the Question.
stich3 [128]

Answer:

Step-by-step explanation:

postulate : ASA

Congruent statement : LON  = MNO

7 0
3 years ago
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