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My name is Ann [436]
3 years ago
8

Six rectangles each with a common base width of 22 have lengths of 1,4,9,16,251,4,9,16,25, and 3636. What is the sum of the area

s of the six rectangles?
Mathematics
1 answer:
Firdavs [7]3 years ago
6 0

The area of the rectangle is the product of the length and the width of the quadrilateral. Hence, the sum of the areas is equal to  $2*1+2*4+2*9+2*16+2*25+2*36$. This is simply equal to $2*(1+4+9+16+25+36)$, which is equal to $2*91$, which is equal to our final answer of 182.
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PLEASE HELP ME Given O below, if XY and YZ are congruent, what is the measure of YOZ
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Step-by-step explanation:

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4 years ago
A container manufacturer plans to make rectangular boxes whose bottom and top measure 2x by 3x. The container must contain 12in.
lisabon 2012 [21]

The height of the container be so as to minimize cost will be 1.20. inches.

<h3>How to calculate the height?</h3>

The volume of the box will be:

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The cost function will be:

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