Let's call this line y=mx+C, whereby 'm' will be its gradient and 'C' will be its constant.
If this line is parallel to the line you've just mentioned, it will have a gradient 2/3. We know this, because when we re-arrange the equation you've given us, we get...

So, at the moment, our parallel line looks like this...
y=(2/3)*x + C
However, you mentioned that this line passes through the point Q(1, -2). If this is the case, for the line (almost complete) above, when x=1, y=-2. With this information, we can figure out the constant of the line we want to find.
-2=(2/3)*(1) + C
Therefore:
C = - 2 - (2/3)
C = - 6/3 - 2/3
C = - 8/3
This means that the line you are looking for is:
y=(2/3)*x - (8/3)
Let's find out if this is truly the case with a handy graphing app... Well, it turns out that I'm correct.
Chandlers salary increased by 5 percent, to find this answer you take his new salary and divide it by its old and the decimal is the percentage increase
It's the bottom one. Miko found the incorrect and checked her work using multipication incorrectly.
This is because the correct way to solve this would to use (5/1) * (3/5) = (15/5) then simplify it to 3/1 or simply 3.
Dividing fractions is simply flipping the second fraction and then multiplying across
F(-1)=81+3e-.7(-1)
enter into scientific/ graphing calculator
f(-1)=89.85
Answer:
A. Between 3.0 and 3.5 and between 4.0 and 4.5
Step-by-step explanation:
The zeroes of a function occur whenever a value of x returns zero. To predict where the zeroes lie, determine the interval(s) where the function crosses the x-axis. This occurs when either
goes from a negative value to a positive value or vice versa.
From
and
, the y-values go from 4.0 (positive) to -0.2 (negative), respectively. Therefore, there must be a zero in this interval.
From
and
, the y-values go from -0.8 (negative) to 0.1 (positive), respectively. Therefore, there must also be a zero in this interval.
Thus, the zeros of this function occur between 3.0 and 3.5 and between 4.0 and 4.5, leading to answer choice A.