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olga2289 [7]
4 years ago
15

-26 times a number minus 5 is equal to 56 less than the number

Mathematics
1 answer:
Airida [17]4 years ago
3 0

-26x - 5 = x - 56

That should be the equation that is formed.

If you are attempting to find said number (x), then follow these steps:

First, add five to both sides:

-26x = x - 51

Then subtract x from both sides to get the variable on one side of the equation:

-27 x = -51

Now, divide both sides by -27, which will get you the final answer of:

x = -1.9 (rounded up)

Hope this helps!

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1.8 or 1 4/5 should be the answer!

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In a school play, girls outnumber boys in the acting cast. There are 33 girls and 17 boys
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17:33

Step-by-step explanation:

if u are asking for the ratio of total boys to total girls the answer above is correct, if not im not sure what ur asking

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What is .the quotient -5 and y ??
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8 0
3 years ago
A department store will place a sale item in a special display for a one-day sale. Previous experience suggests that 43 percent
Svetradugi [14.3K]

Answer:

672.7436 units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale

Step-by-step explanation:

No. of customers pass the display on the day of sale = 1462

Proportion of people will purchase if pass such a special display = 0.43

Mean = E(X)=np

E(X)=1462 \times 0.43

E(X)=628.66

Standard deviation = \sqrt{npq}

Standard deviation =\sqrt{1462 \times 0.43 \times (1-0.43)}=18.92

Now we are supposed to find how many units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale

P(X<x)=0.01

Using z table

P(\frac{x-\mu}{\sigma})= 2.33 \\\frac{x-628.66}{18.92}=2.33\\x=(2.33 \times 18.92)+628.66\\x=672.7436

Hence 672.7436 units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale

5 0
3 years ago
9. In a rhombus whose side measures 34 and the smaller angle is 42°. Find the length of the larger diagonal, to the nearest tent
Veseljchak [2.6K]

Answer:

63.5

Step-by-step explanation:

The diagonals of a rhombus bisect opposite angles.

The longer diagonal bisects the 42° angle

The larger angle of the rhombus is 180 - 42 = 138

Let x = the length of the longer diagonal

You know two sides and the included angle of a triangle.

Using the law of cosines we get

x^{2} = 34^{2} + 34^{2} -2(34)(34) cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.150837...\\x = \sqrt{4030.150837} = 63.48x^{2} = 34^{2} + 34^{2} -2(34)(34)cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.1508...\\     x = \sqrt{4030.1508} \\          =  63.48x^2 = 34^2 + 34^2 - 2(34)(34) cos 138

      = 1156 + 1156 - 2312 c0s 138

      = 4030.1508...

x = sq rt 4030.1508...

  =  63.5

7 0
3 years ago
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