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2 years ago

Missing the y-value in the table?

Mathematics

1 answer:

jeyben [28]2 years ago

3 0

Answer:

-1

Step-by-step explanation:

The constant rate of change is -y for every one x.

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docker41 [41]

I’m pretty sure it’s true

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3 years ago

A six foot tall man casts a shadow that is 10 feet long. if a tree next to the man casts a 25 foot shadow. how tall is the tree?

OLga [1]

Answer: Im not completely sure but my best guess is 21. the tree is 21 feet tall

Step-by-step explanation:

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3 years ago

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KATRIN_1 [288]

Answer:

The maximum height of the volleyball is 12.25 feet.

Step-by-step explanation:

The height of the volleyball, h(t), is modeled by this equation, where t represents the time, in seconds, after that ball was set :

$h(t)=-16t^2+20t+6$ ....(1)

The volleyball reaches its maximum height after 0.625 seconds.

For maximum height,

Put $\dfrac{dh}{dt}=0$

Now put t = 0.625 in equation (1)

$h(t)=-16(0.625)^2+20(0.625)+6\\\\h(t)=12.25\ \text{feet}$

So, the maximum height of the volleyball is 12.25 feet.

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3 years ago

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ivanzaharov [21]

Answer:

False

Step-by-step explanation:

Every where I looked it shows nothing about the Coriolis effect is the measurement of wind speed based on friction from mountains.

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2 years ago

Cos(-170°) = _____<br><br> -cos10°<br> cos10°<br> cos(-10°)

ikadub [295]

<em>The right answer for:</em>

<h2>Explanation:</h2>

The cosine function is an even function, which means that for every point $(x,y)$ on the graph of $y=cos(x)$ then the point $(-x,y)$ also lies on the graph of the function. In other words, we can write:

$cos(-170^{\circ})=cos(170^{\circ})$

But:

$170^{\circ}=180^{\circ}-10^{\circ}$

So:

$cos(170^{\circ})=cos(180^{\circ}-10^{\circ})$

By property:

$cos(a-b)=cosacosb+sinasinb \\ \\ a=180^{\circ} \\ \\ b=10^{\circ} \\ \\ cos(170^{\circ} )=cos(180^{\circ} -10^{\circ})=cos180^{\circ} cos10^{\circ} +sin180^{\circ} sin10^{\circ} \\ \\ cos(170^{\circ})=-cos(10^{\circ})+0 \\ \\ \boxed{cos(170^{\circ})=-cos(10^{\circ})}$

<h2>Learn more:</h2>

Trigonometric functions: brainly.com/question/2680050

#LearnWithBrainly

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3 years ago