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Andrei [34K]
3 years ago
13

Find the standard form of the equation of the parabola with a vertex at the origin and a focus at (0, 9).

Mathematics
1 answer:
Svetllana [295]3 years ago
5 0
First we write standard form that includes both vertex and focus. The formula goes like this:

(x-h)^2 = 4*p*(y-k)

h and k are coordinates of vertex. since vertex is at beginning that means that h=k=0

p is focal lenght and in our case it is 9

expressing al of this we get:
x^2 = 4*9*y
x^2 = 36y
y = 1/36 * x^2
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Solve the equation X/6 +4=16
elena55 [62]

Answer:

x=160

Step-by-step explanation:

\frac{x}{6+4} =16

\frac{x}{10} =16

x=16 \times 10

x=160

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3 years ago
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3 years ago
Write an equation in standard form for:
Tasya [4]
Hello!
When finding the perimeter of a rectangle, you have to consider the properties of a rectangle. A rectangle has two pairs of equal sides where one is the width, while the other one is the length. 
Now looking back at your question, it says "... a rectangle that is x units wide" ⇒ you let the width = x ; this is the same with "y units long" ⇒ length = y. Perimeter can just be : P = 24.  
Therefore,
The equation would be:
x + x + y + y = P. 
2x + 2y = P.
(Sub in P = 24)
∴ 2x + 2y = 24. (This should be your answer.)
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5 0
3 years ago
What are the solutions to the quadratic equation below x^2+20x+100=7​
aleksandrvk [35]

First you must have the quadratic equal to zero. In order to do this you must subtract 7 to both sides

x^2 + 20x + (100 - 7) = 7 - 7

x^2 + 20x + 93 = 0

Now you must find two numbers who's sum equals 20 and their multiplication equal 93

Are there any? NO!

This means that you have to use the formula:

\frac{-b±\sqrt{b^{2} - 4ac} }{2a}

In this case:

a = 1

b = 20

c = 93

\frac{-(20) plus/minus\sqrt{20^{2} - 4(1)(93)} }{2*1}

\frac{-20 plus/minus\sqrt{400 - 372} }{2}

\frac{-20 plus/minus\sqrt{28} }{2}

^^^We must simplify √28

√28 = 2√7

so...

\frac{-20 plus/minus 2\sqrt{7} }{2}

simplify further:

-10 plus/minus\sqrt{7

-10 + √7

or

-10 - √7

***plus/minus = ±

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0
3 years ago
a painter bought 8 gallons of paint just enough to cover 2 rooms. One room is twice the size of the other and requires only 2 co
e-lub [12.9K]
So, he's got 8 gallons of paint, to paint the two rooms, of the two rooms, one is twice as big as the other

now, "x" is how many gallons to paint the larger room with only one coat, however, the larger room uses 2 coats, so, the larger room uses 2x of paint
now, the client declined to paint the smaller one

so hmmm as I read... well, we dunno how many coats will go to the smaller room for one, we know the larger will use 2 coats, or 2x.. if we assume the smaller room was going to use say 1 coat or 1/2x

then one can say the painter bought enough for both rooms, 1coat for the small one and 2coats for the larger one

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thus, with those assumptions, that the small room will use only 1 coat
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now, the client decides to skip the smaller roomso, the painter will only need 2x gallons then

\bf 2x\implies 2\cdot \cfrac{16}{5}\implies \cfrac{32}{5}\implies 6.4\ gallons

he bought 8 gallons, 8 - 6.4, he's got left 1.6 gallons
3 0
3 years ago
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