You have $15 and admission is $5, so you know have $10 before doing any games. If you wanted to play 12 games, you would need $10.20, which you do not have. But, if you wanted to play 11 games, then you would need $9.35, which is just under $10.
So the maximum amount of games that you could play would be 11 games.
Only 3 and 9 are both the subset of odd numbers and the subset of multiples of 3.
horizontal shift: 3 units to the left
vertical shift: 4 units down
Answer:
(x-3,y-4) = correct
Step-by-step explanation:
Sorry for my messy handwriting but this is the answer