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Verizon [17]
3 years ago
15

Please help me lol......

Mathematics
2 answers:
Aleksandr [31]3 years ago
6 0
B could also be correct because The x value is always independent(the time values) and y value is dependent (the distance)
anastassius [24]3 years ago
4 0

Answer:

i think its D no cap lol myb if im wrong (:

Step-by-step explanation:

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Hi, ok all you need to do is use the direct variation formula which is= y/x=y/x so you will replace your numbers by each value which get us to = 3/-6=y/1 so you cross multiply which gives us 3=-6y you divide 3 by -6 and that is the value of y, thank you for reading hope it helps ;)
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For the piecewise Function below, which of the following statments is true? Someone please help me
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When somebody tells there friend there da best does that mean they think that they’re better then anyone else???
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Step-by-step explanation:

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Halla la tasa de variación de cada funcion en el intervalo [-4,3] e indica si es positiva , negativa o nula A) f(x)=x2-2x+4 B) f
masya89 [10]

Answer:

A) \hspace{3}Rate\hspace{3}of\hspace{3}change=-5\hspace{3}Negative\\\\B)\hspace{3}Rate\hspace{3}of\hspace{3}change=-21\hspace{3}Negative  

Step-by-step explanation:

Given a function f(x), we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value "x_1" to another "x_2".

The rate of change of f(x) between x_1 and x_2 can be calculated as follows:

Rate\hspace{3}of\hspace{3}change=f(x_2)-f(x_1)

For:

f(x)=x^2-2x+4

Let's find f(x_1) and f(x_2), where:

[x_1,x_2]=[-4,3]

f(x_1)=f(-4)=(-4)^2-2(4)+4=16-8+4=12\\f(x_2)=f(3)=(3)^2-2(3)+4=9-6+4=7

So:

Rate\hspace{3}of\hspace{3}change =7-12=-5\hspace{3}Negative

And for:

f(x)-3x+2

Let's find f(x_1) and f(x_2), where:

[x_1,x_2]=[-4,3]

f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7

So:

Rate\hspace{3}of\hspace{3}change =-7-14=-21\hspace{3}Negative

<em>Translation:</em>

Dada una función f(x), llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor "x_1" a otro "x_2".

La tasa de variación de f(x) entre x_1 y x_2, puede ser calculada de la siguiente forma:

Tasa\hspace{3}de\hspace{3}variacion=f(x_2)-f(x_1)

Para:

f(x)=x^2-2x+4

Encontremos f(x_1) y f(x_2), donde:

[x_1,x_2]=[-4,3]

f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7

Entonces:

Tasa\hspace{3}de\hspace{3}variacion =7-12=-5\hspace{3}Negativa

Y para:

f(x)-3x+2

Encontremos f(x_1) y f(x_2), donde:

[x_1,x_2]=[-4,3]

f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7

Entonces:

Tasa\hspace{3}de\hspace{3}variacion=-7-14=-21\hspace{3}Negativa

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koban [17]

Answer:

1/p^2

Step-by-step explanation:

To get rid of a negative exponent, make it under a 1/

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3 years ago
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