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Digiron [165]
3 years ago
9

Examine the first two steps for solving this equation. 3x - 6(5x + 3) = 9x + 6 1. Distribute: 3x - 30x - 18 = 9x + 6 2. Combine

like terms: -27x - 18 = 9x + 6 What could be the coefficient of x once the variable term is isolated on one side of the equation? Check all that apply. –36 –27 –24 24 27 36
Mathematics
2 answers:
julsineya [31]3 years ago
6 0

The Coefficient of variable term x after making it isolated would be -36

Step-by-step explanation:

We have to solve the equation in order to get the coefficient of x at the end after isolation.

Given

3x - 6(5x + 3) = 9x + 6

Distribute

3x - 30x - 18 = 9x + 6

Combine like terms:

-27x - 18 = 9x + 6

subtracting 9x from both sides

-27x - 18-9x = 9x + 6-9x\\-36x-18=6

We can clearly see that the coefficient of x at the end after it has been isolated is -36

Hence,

The Coefficient of variable term x after making it isolated would be -36

Keywords: Linear Equation, Variable

Learn more about linear equation at:

  • brainly.com/question/4522984
  • brainly.com/question/4550858

#LearnwithBrainly

katrin2010 [14]3 years ago
6 0

Answer:

-36 and 36

Step-by-step explanation:

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Angle Number<br> Measure<br> 1<br> 2<br> 13<br> 1<br> 1267<br> 2<br> 3
Serggg [28]

Answer:

∠1=54°

∠2=54°

∠3 = 126°

Step-by-step explanation:

We need to find ∠1, 2 and 3

Since a traversal cut parallel lines we would use supplementary angles , congruent angles rules to solve the problem.

Angle 1 and 126 are supplementary angles.

They add up to make 180

So, ∠1 + 126 = 180

∠1 = 180-126

∠1 =54

We get ∠1=54°

Now, ∠1 ≅ ∠2, because they are corresponding angles and if traversal cut parallel lines, corresponding angles are congruent.

So ∠1 ≅ ∠2 therefore, ∠2=54°

Now, for finding measure for ∠3, we know that 126 and ∠4 are corresponding angles and corresponding angles are congruent.

So, ∠4 = 126°

We know that ∠3 and ∠4 are vertical angles.

And if traversal cut parallel lines, vertical angles angles are congruent.

So, ∠3 = 126°

8 0
3 years ago
There are 20 flowers in a bouquet, and 2 of them are roses. What percent of the flowers are roses?
Diano4ka-milaya [45]

Answer

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Step-by-step explanation:

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(problem 83)
AVprozaik [17]

To find the derivative of this function, there is a property that we should know called the Constant Multiple Rule, which says:

\dfrac{d}{dx}[cf(x)] = cf'(x) (where c is a constant)


Remember that the derivative of \csc(x) is -\csc(x)\cot(x). However, you may notice that we are finding the derivative of \dfrac{1}{2}\csc(2x), not \dfrac{1}{2} \csc(x). So, we are going to have to use the chain rule. To complete the chain rule for the derivative of a trigonometric function (in layman's terms) is basically the following: First, complete the derivative of the trig function as you would if what was inside the trig function is x. Then, take the derivative of what's inside of the trig function and multiply it by what you found in the first step.


Let's apply that to our problem. Right now, I am not going to worry about the \dfrac{1}{2} at the front of the equation, since we can just multiply it back in at the end of our problem. So, let's examine \csc(2x). We see that what's inside the trig function is 2x, which has a derivative of 2. Thus, let's first find the derivative of \csc(2x) as if 2x was just x and then multiply it by 2.


The derivative of \csc(2x) would first be -\cot(2x)\csc(2x). Multiplying it by 2, we get our derivative of -2\cot(2x)\csc(2x). However, don't forget to multiply it by the \dfrac{1}{2} that we removed near the beginning. This gives us our final derivative of -\cot(2x)\csc(2x).


Remember that we now have to find the derivative at the given point. To do this, simply "plug in" the point into the derivative using the x-coordinate. This is shown below:

-\cot[2(\dfrac{\pi}{4})]\csc[2(\dfrac{\pi}{4})]

-\cot(\dfrac{\pi}{2})\csc(\dfrac{\pi}{2})

-(0)(1) = \boxed{0}


Our final answer is 0.

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Setler79 [48]

Answer:

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then the 24 ft= 24/4=6

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