All categories

3 years ago

Which number between 20 and 28 are prime

Mathematics

2 answers:

ollegr [7]3 years ago

8 0

The number is 23, that is the only number prime between 20 and 28

ad-work [718]3 years ago

4 0

Prime numbers basically numbers that dont have any numbers that will be multiplied to get to it. So, it would be:
23
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
All the other numbers in between can be divided by something and not become a decimal. Other than 23, it can be divided by anything without becoming a decimal.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
~Hope this helped :)

You might be interested in

Solving for x and y in a linear equation (x,y) -11x-10y=17 5x-7y=50

Elena-2011 [213]

Top one
y=-1.7+11y
x=-1.55+10y
Bottom one
y=-7.14-5x

5 0

3 years ago

Read 2 more answers

Find the greatest common factor of 63 and 96

julia-pushkina [17]

The greatest common factor (GCF) of 63 and 96 is: 3

To find the GCF, list all the factors until that go up to 63 since that is the minimum.
Factors of 63: 1, 3, 7, 9, 21, 63
Factors of 96: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48

Find the common factors between the two numbers which are 1 and 3. Now, which one of those numbers are the greatest/highest? The answer is 3.

4 0

3 years ago

Read 2 more answers

PLEASE HELP I AM BEING TIMED!

german

Answer: C.) Congruent (or third option)

3 0

3 years ago

Two sets of equatic expressions are shown below in various forms: Line 1: x2 + 3x + 2 (x + 1)(x + 2) (x + 1.5)2 − 0.25 Line 2: x

kherson [118]

Answer: The correct line is

$\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.$

Step-by-step explanation: We are given the following two sets of quadratic expressions in various forms:

$\textup{Line 1: }x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25,\\\\\textup{Line 2 :}x^2+5x+6=(x+2)(x+3)=(x+2.5)^2+6.25.$

We are to select one of the lines from above that represent three equivalent expressions.

We can see that there are three different forms of a quadratic expression in each of the lines:

First one is the simplified form, second is the factorised form and third one is the vertex form.

So, to check which line is correct, we need to calculate the factorised form and the vertex form from the simplified form.

We have

$\textup{Line 1: }\\\\x^2+3x+2\\\\=x^2+2x+x+2\\\\=x(x+2)+1(x+2)\\\\=(x+1)(x+2),$

and

$x^2+3x+2\\\\=x^2+2\times x\times 1.5+(1.5)^2-(1.5)^2+2\\\\=(x+1.5)^2-2.25+2\\\\=(x+1.5)^2-0.25.$

So,

$\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.$

Thus, Line 1 contains three equivalent expressions.

Now,

$\textup{Line 2: }\\\\x^2+5x+6\\\\=x^2+3x+2x+6\\\\=x(x+3)+2(x+3)\\\\=(x+2)(x+3),$

and

$x^2+5x+6\\\\=x^2+2\times x\times 2.5+(2.5)^2-(2.5)^2+6\\\\=(x+2.5)^2-6.25+6\\\\=(x+2.5)^2-0.25\neq (x+2.5)^2+6.25.$

So,

$\textup{Line 2 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2+6.25.$

Thus, Line 2 does not contain three equivalent expressions.

Hence, Line 1 is correct.

7 0

3 years ago

Help me, please this isn't really so hard, but I really need help

Oxana [17]

Answer:

what topic???????????????????

3 0

2 years ago