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uranmaximum [27]
3 years ago
8

Find the area of a circle with radius of 9

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
6 0

The formula for the area of a circle is Area = \pir^{2}

Since the radius of the circle is 9 cm, we can plug 9 cm in for the radius in our formula. Now we have

\pi (9 cm)^{2}. Remember that 9 cm ^{2} is the same thing as 9 cm × 9 cm.

\pi (9 cm) (9 cm) = 81\picm^{2}

Andreyy893 years ago
5 0

Answer:

The area of the circle would be 254.47

Hope this helps!!

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How <br> do you write (-∞, 8) or (10, ∞) as an inequality?
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Your answer would be, To write, (−∞,8), or (10,∞), ==> x < 8 or, x > 10

(-∞, 8) or (10, ∞)

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Steps:

(-∞, 8) or (10, ∞) ==> - 10 . ∞ + 8 . ∞

(-∞, 8) . (10, ∞)

Computing dot product of two Vectors:

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Simplify:

( - ∞) 10 + 8 . ∞

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( - ∞) . 10 + 8 . ∞

Remove Parenthesis:

( - a) ==> - a

- ∞ . 10 + 8 . ∞

==> - 10 . ∞ + 8 . ∞

==> (- 10 . ∞ + 8 . ∞) ==> - 10 . ∞ + 8 . ∞

( ==> - 10 . ∞ + 8 . ∞)

Remove Parenthesis:

( a) = a

==> - 10 . ∞ + 8 . ∞

Therefore, (-∞, 8) or (10, ∞) as an inequality, Answers are, ==>

- 10 . ∞ + 8 . ∞ or, x < 8 or, x > 10

Check:

(-∞, 8) or (10, ∞)

==> x < 8 or, x > 10

Solution:

x < 8 or, x > 10

Interval Notation:

[ x < 8 or, x > 10 ==> (-∞, 8) ∪ (10, ∞) ]

Steps:

x < 8 or, x > 10

x < 8 : x < 8

x < 8

x < 8

x < 8

x > 10 : x > 10

x > 10

x > 10

x > 10

Combine The Ranges:

x < 8, or x > 10

Hope that helps!!!!! : )

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