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3 years ago

1 Which relation is not a function?

Mathematics

2 answers:

Karo-lina-s [1.5K]3 years ago

6 0

3 because the x value has been repeated

gizmo_the_mogwai [7]3 years ago

3 0

3) {(−1,6),(1,3),(2,5),(1,7)}

Step-by-step explanation:

functions have to pass the vertical line test to be called a function

if they don't pass they are not a function

this means that no x values can repeat

In option 1

none of the x values repeat so that means it is a function

1, 2, 3, 4

in option 2

none of the x values repeat so that means it is a function

4,2,-3,3

in option 3

one of the x values repeats so that means it is not a function

-1,1,2,1  the ones repeat

in option 4

none of the x values repeat so that means it is a function

-1,0,5,2

so that means that option 3 is not a function 

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X²+Y²=250 and XY=117 What are the values of X and Y?

yan [13]

Answer:

Step-by-step explanation:

$x^2+y^2=250\\\\x^2-2xy+y^2+2xy=250\\\\(x-y)^2=250-2xy\\\\(x-y)^2=250-2\cdot117\\\\ (x-y)^2=16\\\\x-y=4\qquad\qquad\vee\qquad \qquad x-y=-4\\\\x=4+y \qquad\qquad \vee\qquad\qquad x=-4+y\\\\(y+4)y=117\qquad\vee\qquad\quad (y-4)y=117\\\\y^2+4y-117=0\qquad\vee\qquad y^2-4y-117=0\\\\y=\dfrac{-4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\qquad\vee\qquad y=\dfrac{4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\\\\y=\dfrac{-4\pm\sqrt{16+468}}{2}\qquad\ \ \vee\qquad y=\dfrac{4\pm\sqrt{16+468}}{2}$

$y_1=\dfrac{-4-22}{2}\ ,\quad y_2=\dfrac{-4+22}{2}\ ,\quad y_3=\dfrac{4-22}{2}\ ,\quad y_4=\dfrac{4+22}{2}\\\\y_1=-13\ ,\qquad y_2=9\ ,\qquad\quad\qquad\ y_3=-9\ ,\qquad y_4=13\\\\x_{1,2}=4+y_{1,2}\qquad\qquad\qquad\qquad\qquad x_{3,4}=-4+y_{3,4}\\\\x_1=-9\ ,\qquad x_2=13\ ,\qquad\quad\qquad x_3=-13\ ,\qquad x_4=9$

6 0

3 years ago

Find the degree measure of each angle in the triangle.

Alex777 [14]

Answer:

∠R = 56°
∠Q = 90°
∠S = 34°

Step-by-step explanation:

The given triangle is a right angled triangle.

So, the angles in the triangle are :

90°
(2x + 38)°
(5x - 11)°

Solving according to angle sum property,

Sum of all angles in a triangle is 180°

$\longrightarrow$ 90° + (2x + 38)° + (5x - 11)° = 180°

$\longrightarrow$ 117° + 7x = 180°

$\longrightarrow$ 7x = 180° - 117°

$\longrightarrow$ 7x = 63°

$\longrightarrow$ x = 9

Angles =

$\longrightarrow$ 2(9) + 38

$\longrightarrow$ 56°

$\longrightarrow$ 5(9) - 11

$\longrightarrow$ 34°

∠R = 56°
∠Q = 90°
∠S = 34°

The angles are 56°, 90° and 34°.

4 0

3 years ago

Im not sure how to explain my question in words so its in the file below- ;-;

eimsori [14]

Answer:

Step-by-step explanation:

The arrow is pointing right is it is greater than which means that A and B are out. And for

D, -4 is not greater than -3 so D is also out which leaves only C

and -2 is greater than -3

4 0

3 years ago

Read 2 more answers

Solve the system y = -x + 7 and y = -0.5(x - 3)^2 + 8.

AlladinOne [14]

Answer:

(1,6) & (7,0)

Step-by-step explanation:

y = -x + 7

y = -0.5(x - 3)² + 8

To solve the system, solve these two equations simultaneously

-x + 7 = -0.5(x - 3)² + 8

-x + 7 = -0.5(x² - 6x + 9) + 8

-x + 7 = -0.5x² + 3x - 4.5 + 8

0.5x² - 4x + 3.5 = 0

x² - 8x + 7 = 0

x² - 7x - x + 7 = 0

x(x - 7) - (x - 7) = 0

(x - 1)(x - 7) = 0

x = 1, 7

y = -1 + 7 = 6

y = -7 + 7 = 0

(1,6) (7,0)

Since the system has two distinct solutions, the line and the curve meet at two distinct poibts9: (1,6) & (7,0)

8 0

3 years ago

find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B

SashulF [63]

Answer:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

$a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10$