Answer:
2s or 3s
Step-by-step explanation:
Given the function that models the height of the object as;
h(t) = - 16t^2 + 80t + 96
The ball reaches the ground when h = 0
Substitute
0 = - 16t^2 + 80t + 96
Divide through by -16
0 = t²-5t-6
t²-5t-6 = 0
t²-2t-3t+6 = 0
t(t-2)-3(t-2) = 0
(tt-2)(t-3) = 0
t - 2 = 0 and t-3 = 0
t = 2 and 3s
Hence it will take the ball 2s or 3s to reach the ground
1/3 if you have a positive and a negative, it will turn into a positive so 11/12-7/12
Answer:
8
Step-by-step explanation:
Let s represent the length of the shorter base and height. Then (3/2)s is the length of the longer base.
The area formula for a trapezoid is ...
A = 1/2(b1 +b2)h
Filling in the given values, we have ...
80 = (1/2)(s +3/2s)s = 5/4s²
64 = s² . . . . . . . . . . . . . . . . . . . multiply by 4/5
8 = s . . . . . . . . . . . . . . . . . . . . . take the square root
The length of the shorter side is 8.
The answer is 3n9 units. So the second one
Answer:
Step-by-step explanation:
Let the number be 'x'
Quotient of a number and 4 = 
Six less than the quotient of a number and 4 : 
Equation:
