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3 years ago

I can't figure out what I'm doing wrong can you please help me I'll give you a lot of points and this this really hard :(

Mathematics

1 answer:

andre [41]3 years ago

4 0

Answer:

1,495,672

Step-by-step explanation:

Build a table to track the number of adult rats, 3-week old rats (let's call them teens), and baby rats.

$\left[\begin{array}{ccccc}Week&Adult&Teen&Baby\\1&2&0&0\\3&2&0&10\\6&2&10&10\\9&12&10&10\\12&22&10&60\\15&32&60&110\\18&92&110&160\end{array}\right]$

The pattern is this: every 3 weeks, the number of adults becomes the previous number of adults + the number of teens. The number of teens becomes the previous number of babies. And the number of babies becomes the previous number of adults × 5.

Continuing:

$\left[\begin{array}{ccccc}Week&Adult&Teen&Baby\\1&2&0&0\\3&2&0&10\\6&2&10&10\\9&12&10&10\\12&22&10&60\\15&32&60&110\\18&92&110&160\\21&202&160&460\\24&362&460&1010\\27&822&1010&1810\\30&1832&1810&4110\\33&3642&4110&9160\\36&7752&9160&18210\\39&16912&18210&38760\\42&35122&38760&84560\\45&73882&84560&175610\\48&158442&175610&369410\\51&334052&369410&792210\end{array}\right]$

So at the end of the year, there are a total of 1,495,672 rats.

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There are 45 cards in a card game deck. How many cards in 4 decks?

Alex_Xolod [135]

Answer:

180 cards

Step-by-step explanation:

45x 4= 180

6 0

2 years ago

If a+b+c=6,ab+bc+ca=11,then what is a3+b3+c3-3abc

kipiarov [429]

(a+b+c)^3=a^3 +b^3+c^3-2(ab+ac+bc)

216=a^3+b^3+c^3-2(11)

a^3+b^3+c^3=238

but ıdk how can ı find -3abc :/

7 0

3 years ago

Read 2 more answers

Boris chooses three different numbers the sum of the three numbers is 36 one of the numbers is a cube number the other two numbe

OlgaM077 [116]

Answer:

3,4,5

Step-by-step explanation:

Here, we need to asume that the values are integers, as if not, there will be infinite solutions.

Lets go by parts:

The 1st number is a cubic, lets call it A

The second is a factor of 20, lets call it B. The same for the 3rd, call it C.

So, A + B+ C = 36

There are no many factors of 20, those are the numbers that when multiplied gives as the value of 20. Those are 1, 2, 4, 5, 10 and 20. So, B and C are some of these numbers.

Then, we know A if less than 36, other way the whole sum will be greater than 36. How many cubic number with integer cubic roots are less than 36? Well, lets guess:

1^3 = 1 -> valid, as it is less than 36

2^3 = 8 -> valid, as it is less than 36

3^2 = 27 -> valid, less than 36

4^3 = 64 -> not valid, as it is greater than 36

So, A ir 1, 2 or 3.

If A is 1, then B+C needs to be 35. But, from the factors of 20 that we listed, there are no combinations of 2 numbers that sum 35. So, A CAN'T be 1.

If A = 2, then we have:

8 + B + C = 36

B + C = 28

And again, there are not combinations of two factors of 20 that sum 28 (try yourself).

If A=3:

27 + B + C = 36

B +C = 9

And we have a winner!!! If B=4 and C=5 (or viceversa C=4 and B=5)

27 + 4 + 5 = 36

So, A=3, B=4 and C=5 or A=3, C=4 and B=5 are solutions.

3 0

4 years ago

As James bought his textbooks for classes one semester, he estimated the cost to the nearest ten dollars. He knew he could cover

TEA [102]

Answer:

$310

Step-by-step explanation:

The first step is to add the costs of the textbook together :

$68.41 + $105.35 + $72.49 + $59.91 = $306.16

In order to round off to the nearest ten dollars, look at the units figure, if the number is greater or equal to 5, add 1 to the ten figure. If this is not the case, add zero. Replace the unit digit with zero

The unit digit is greater than 6, so 1 is added to the tens digit. The amount becomes $310

8 0

3 years ago

How do I do this ffs

lidiya [134]

Answer:

I am not sure but for me the answer is 1

6 0

3 years ago