The correct answer is A square root of 41
Answer: a) (176.76,172.24), b) 0.976.
Step-by-step explanation:
Since we have given that
Mean height = 174.5 cm
Standard deviation = 6.9 cm
n = 50
we need to find the 98% confidence interval.
So, z = 2.326
(a) Construct a 98% confidence interval for the mean height of all college students.

(b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 174.5 centime- ters?
Error would be

Hence, a) (176.76,172.24), b) 0.976.
The "dot product" of two vectors has several different formulas.
Since you are given the x- and y-coordinates of both vectors a and b, we can apply the formula
a dot b = ax*bx + ay*by, where ax=x-component of vector a, by=y comp of vector b, and so on.
So, for the problem at hand, ax * bx + ay * by becomes
3(-2) + (-8)(-6) = -6 + 48 = 42 (answer). Note that the dot product (or "scalar product" is itself a scalar.

by using the integration formula
we get,

now put the value of t=\sin\theta in the above equation
we get,

hence proved
The second step is wrong. What should've been done is to find greatest common factor (gcf) of 1/6 and -2. This is because you cannont add together a number with a variable to a number without a variable. So get the variable by itself by subtracting 1/6 from both sides.
1/5x + 1/6 = -2
___— 1/6_— 1/6
____________
Turn -2 into a fraction and find the gcf of -2 and 6:
1/5x + 1/6 = -2
___— 1/6_— 1/6
____________
1/5x = -2/1 — 1/6 ——> 1/5x = -12/6 — 1/6
1/5x = -13/6
Then divide each side by 1/5 to get the variable by itself; remeber: when dividing a fraction by a fraction, you multiply by the reciprocal.
5/1 • 1/5x = -13/6 • 5/1
x = 65/6
Then, simplify
65/6} 10.83 or 10 83/100