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2 years ago

The length of a rectangle is four times its width.

Mathematics

1 answer:

MArishka [77]2 years ago

5 0

Is the answer 240.is that one of your options

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m∠1 is 4 times m∠2. ∠1 and ∠2 are complementary. ∠1 and ∠3 are vertical angles. ∠3 and ∠4 are supplementary. What are the measur

kherson [118]

Answer:

Step-by-step explanation:

Let's write a system of equations. I'm going to call them w, x, y, and z.

w = 4x (because m∠1 is 4 times m∠2)

w + x = 90 (bc ∠1 and ∠2 are complementary, meaning they add up to 90)

w = y (bc ∠1 and ∠3 are vertical angles, meaning they are equal)

y + z = 180 (bc ∠3 and ∠4 are supplementary, meaning they add up to 180)

When we substitute w=4x into the second equation, we get 5x=90 → m∠2 = 18°. Since w=4x, m∠1 = 18*4 = 72°. Since w=y, m∠3 = 18°. Finally, because y+z=180, m∠4 = 180-18 = 162°. Hope this helps!

3 0

2 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Rina8888 [55]

83 hope it helps get a good grade

4 0

3 years ago

Read 2 more answers

2 ways to decompose the number 749

kolezko [41]

Okay. You can decompose 749 with these ways:
700 + 40 + 9
or
500 + 200 + 40 + 9

6 0

2 years ago

The volume V of an ice cream cone is given by V = 2 3 πR3 + 1 3 πR2h where R is the common radius of the spherical cap and the c

Nuetrik [128]

Answer:

The change in volume is estimated to be 17.20 $\rm{in^3}$

Step-by-step explanation:

The linearization or linear approximation of a function $f(x)$ is given by:

$f(x_0+dx) \approx f(x_0) + df(x)|_{x_0}$ where $df$ is the total differential of the function evaluated in the given point.

For the given function, the linearization is:

$V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh$

Taking $R_0=1.5$ inches and $h=3$ inches and evaluating the partial derivatives we obtain:

$V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh\\V(R, h) = V(R_0, h_0) + (\frac{2 h \pi r}{3} + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh$

substituting the values and taking $dx=0.1$ and $dh=0.3$ inches we have:

$V(R_0+dR, h_0+dh) =V(R_0, h_0) + (\frac{2 h \pi r}{3} + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh\\V(1.5+0.1, 3+0.3) =V(1.5, 3) + (\frac{2 \cdot 3 \pi \cdot 1.5}{3} + 2 \pi 1.5^2)\cdot 0.1 + (\frac{\pi 1.5^2}{3} )\cdot 0.3\\V(1.5+0.1, 3+0.3) = 17.2002\\\boxed{V(1.5+0.1, 3+0.3) \approx 17.20}$

Therefore the change in volume is estimated to be 17.20 $\rm{in^3}$

4 0

2 years ago

A football team loses an average of 3 yards per play. How many yards

Minchanka [31]

The expression would be:

x=number of plays

Insert 4:

3(4)

=12

They would 12 yards after 4 plays if losing 3 yards every play.

5 0

2 years ago