First, find what percentage of students had 3 or more by adding up your known percents:
45% + 23 % + 21% + x% = 100%
x = 11%
Since you're given that 96 students had 2 or more, you add up the percentages of 2 and 3 or more:
11 + 21 = 32%
Now set up a proportion that relates it to the whole:

This will allow you to find the total number of students at the school.
Cross multiplying and solving for x results in 300 total students.
Question 1:
45% had one or more absences. 45% of 300 students is
135 students.
Question 2:
As we found before, 11% of students had three or more. 11% of 300 is
33 students.
Answer:
V = 4/3 π r 3
Step-by-step explanation:
Hope this helps!!
Another way to ask this question: where the x-value of function g equals 12, what's the y-value?
remember that function notation is like so: f(x), g(x), h(x)... so the number in the parentheses is an x-value from the function.
look through your points and find the one that represents an x-value of 12. (12, 19) is the point, and 19 is your output--so, g(12) = 19.
Answer:
Step-by-step explanation:
let the consecutive even numbers be 2n-2,2n,2n+2,2n+4 where n>0 and n is an integer.
2n(2n+2)-(2n-2)(2n+4)
=4n²+4n-(4n²+8n-4n-8)
=4n²+4n-4n²-8n+4n+8
=8