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3 years ago

Solve the equation 3(2x+2)=3x-15x=-7x=-17/3x=3x=7

Mathematics

2 answers:

Reika [66]3 years ago

6 0

Answer:

all work is shown and pictured

Nady [450]3 years ago

4 0

3(2x+2)=3x-15

mutiply the bracket by 3

(3)(2x)(3)(2)= 6x+6

6x+6= 3x-15

move 3x to the other side

sign changes from +3x to -3x

6x-3x+6= 3x-3x-15

6x-3x+6= -15

3x+6= -15

move +6 to the other side

sign changes from +6 to -6

3x+6-6= -15-6

3x= -21

divide by 3 for both sides

3x/3= -21/3

x= -7

Answer: x= -7

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3 years ago

Slope from two points

Goshia [24]

Answer:

$\frac{12}{7}$

Step-by-step explanation:

use the formula $\frac{y - y'}{x - x'}$

so you would get

$\frac{4 - (-8)}{0 - (-7)}$

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7 0

3 years ago

Read 2 more answers

Factor the polynomial completely x^2-x-20

Strike441 [17]

Answer:

(x − 5) (x + 4)

Step-by-step explanation:

x² − x − 20

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1 × -20 = -20

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Divide by 1 and reduce: -5/1 and 4/1

(x − 5) (x + 4)

5 0

4 years ago

Read 2 more answers

Consider two stocks. Stock 1 always sells for $10 or $20. If stock 1 is selling for $10 today, there is a .80 chance that it wil

Hitman42 [59]

Answer:

On stock 2 will be has an average sell of $50 for higher price.

Step-by-step explanation:

stock 1 of $10 (today)+ $10 (80% chance tommorow)=$20 stock sell price and for $20(today)+$20(90% chance tommorow)= $40 this two final of price for stock 1.

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Hope this helps you

5 0

3 years ago

NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. One hundred tickets

Elden [556K]

Answer:

The total number of ways the person holding ticket 47 wins one of the prizes = 941,094

Step-by-step explanation:

Given - One hundred tickets, numbered 1, 2, 3, . . . , 100, are sold to 100 different people for a drawing. Four different prizes are awarded, including a grand prize (a trip to Tahiti).

To find - How many ways are there to award the prizes if it satisfies the given conditions. The person holding ticket 47 wins one of the prizes.

Proof -

The order of selection is important because 1st selection is grand prize , 2nd selection is second prize and so on . So , we use permutation for this question

Now,

As The person holding ticket 47 wins one of the prizes and other 3 prizes are also given to the remaining 99 persons who got chosen

So,

The number of ways = 1* ⁹⁹P₃

= $\frac{99!}{(99-3)!}$

= $\frac{99!}{96!}$

= $\frac{99*98*97*96!}{96}$

= 99*98*97

= 941,094

∴ we get

Total number of ways the person holding ticket 47 wins one of the prizes = 941,094

7 0

3 years ago

Solve the equation 3(2x+2)=3x-15x=-7x=-17/3x=3x=7​

Solve the equation 3(2x+2)=3x-15x=-7x=-17/3x=3x=7