Write the equation, in slope-intercept form, of the line that has a slope of 2 and passes through the point (3, 1).

Miguel and three of his friends went to the movies. They originally had a total of $40. Each boy had the same amount of money an

Alenkasestr [34]

Answer:

The money each boy had after buying his ticket is <u>$2.50</u>.

Step-by-step explanation:

Given:

Miguel and three of his friends went to the movies. They originally had a total of $40. Each boy had the same amount of money and spent $7.50 on a ticket.

Now, to find the money each boy had after buying his ticket.

Let the money each boy had after buying his ticket be $x.$

Total number of boys = 4.

Total money they had = $40.

Money each boy spent = $7.50.

Now, to write an equation:

$4(x+7.50)=40$

Now, to solve the equation for getting the money each boy had after buying his ticket:

$4(x+7.50)=40$

$4x+30=40$

<em>Subtracting both sides by 30 we get:</em>

$4x=10$

<em>Dividing both sides by 4 we get:</em>

$x=\$2.50.$

Therefore, the money each boy had after buying his ticket is $2.50.

3 0

3 years ago

Show work and Evaluate 3/4 + 2/5

frez [133]

Answer:

23/20

Step-by-step explanation:

Find the common denominator of the 2 fractions (It's 20):

3/4 + 2/5

Multiply both numerator and denominator by 5 for the first fraction and multiply by 4 for the second fraction:

15/20 + 8/20

Add the fractions together:

23/20

5 0

3 years ago

Daniel rides his bicycle 21km west and then 18km north. How far is he from his starting point?

insens350 [35]

This is a right triangle. To find the length of the hypotenuse a^2 + b^2 = c^2.

21^2 + 18^2 = c^2

441 + 324 = c^2

765 = c^2

27.66 km

6 0

4 years ago

40% de cuanto son 32?

OlgaM077 [116]

Do not speak Spanish

4 0

4 years ago

Read 2 more answers

A fair die is cast four times. Calculate

svetlana [45]

Step-by-step explanation:

<h2><em><u>You can solve this using the binomial probability formula.</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows:</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: </u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) </u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154when x=4 (4 4)(1/6)^4(5/6)^4-4 = 0.0008</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154when x=4 (4 4)(1/6)^4(5/6)^4-4 = 0.0008Add them up, and you should get 0.1319 or 13.2% (rounded to the nearest tenth)</u></em></h2>

8 0

3 years ago