Solve for x. x/3 = 5/8 8/15 1 7/8 4 4/5

If someone could help me I would really really really appreciate it

nata0808 [166]

Answer:

BC

Step-by-step explanation:

The longest side has the greatest angle opposite to it, 85 deg is the greatest angle, BC is the longest side

3 0

4 years ago

Read 2 more answers

Pls help me on this i don't know what to do

Katarina [22]

Answer:

$\text{A. The zeroes are 8 and -4, because }y=(x-8)(x+4)$

Step-by-step explanation:

$x^2-4x-32=0,\\(x-8)(x+4)=0,\\\begin{cases}x-8=0, x=\boxed{8},\\x+4=0, x=\boxed{-4}\end{cases}$

8 0

3 years ago

Let z denote a random variable that has a standard normal distribution. Determine each of the probabilities below. (Round all an

Gelneren [198K]

Answer:

(a) P (Z < 2.36) = 0.9909 (b) P (Z > 2.36) = 0.0091

(c) P (Z < -1.22) = 0.1112 (d) P (1.13 < Z > 3.35) = 0.1288

(e) P (-0.77< Z > -0.55) = 0.0705 (f) P (Z > 3) = 0.0014

(g) P (Z > -3.28) = 0.9995 (h) P (Z < 4.98) = 0.9999.

Step-by-step explanation:

Let us consider a random variable, $X \sim N (\mu, \sigma^{2})$ , then $Z=\frac{X-\mu}{\sigma}$ , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, $Z \sim N (0, 1)$ .

In statistics, a standardized score is the number of standard deviations an observation or data point is above the mean. The z-scores are standardized scores.

The distribution of these z-scores is known as the standard normal distribution.

(a)

Compute the value of P (Z < 2.36) as follows:

P (Z < 2.36) = 0.99086

≈ 0.9909

Thus, the value of P (Z < 2.36) is 0.9909.

(b)

Compute the value of P (Z > 2.36) as follows:

P (Z > 2.36) = 1 - P (Z < 2.36)

= 1 - 0.99086

= 0.00914

≈ 0.0091

Thus, the value of P (Z > 2.36) is 0.0091.

(c)

Compute the value of P (Z < -1.22) as follows:

P (Z < -1.22) = 0.11123

≈ 0.1112

Thus, the value of P (Z < -1.22) is 0.1112.

(d)

Compute the value of P (1.13 < Z > 3.35) as follows:

P (1.13 < Z > 3.35) = P (Z < 3.35) - P (Z < 1.13)

= 0.99960 - 0.87076

= 0.12884

≈ 0.1288

Thus, the value of P (1.13 < Z > 3.35) is 0.1288.

(e)

Compute the value of P (-0.77< Z > -0.55) as follows:

P (-0.77< Z > -0.55) = P (Z < -0.55) - P (Z < -0.77)

= 0.29116 - 0.22065

= 0.07051

≈ 0.0705

Thus, the value of P (-0.77< Z > -0.55) is 0.0705.

(f)

Compute the value of P (Z > 3) as follows:

P (Z > 3) = 1 - P (Z < 3)

= 1 - 0.99865

= 0.00135

≈ 0.0014

Thus, the value of P (Z > 3) is 0.0014.

(g)

Compute the value of P (Z > -3.28) as follows:

P (Z > -3.28) = P (Z < 3.28)

= 0.99948

≈ 0.9995

Thus, the value of P (Z > -3.28) is 0.9995.

(h)

Compute the value of P (Z < 4.98) as follows:

P (Z < 4.98) = 0.99999

≈ 0.9999

Thus, the value of P (Z < 4.98) is 0.9999.

**Use the z-table for the probabilities.

3 0

3 years ago

Last year Eileen spent $45 on her brother's birthday present. This year she spent $25 more than that. How much did she spend on

luda_lava [24]

Answer:

She spent 70 dollars on his birthday present.

Step-by-step explanation:

Its just 45 plus 25.

3 0

3 years ago

The profits of life insurance companies A and B are normally distributed with the same mean. The variance of company B's profit

Lerok [7]

Answer:

23.58-th

Step-by-step explanation:

The standard deviation of company B's profit is:

$\sigma_B=\sqrt{2.25}\sigma_A$

Let X be the profit correspondent to the 14th percentile of company A's profit.

The z-score for 14th percentile of a normal distribution is roughly -1.08.

The z-scores for X in companies A and B are:

$-1.08 = \frac{X-\mu}{\sigma_a} \\z_B = \frac{X-\mu}{\sqrt{2.25}*\sigma_a}\\z_B=\frac{-1.08}{\sqrt{2.25}}\\z_B = -0.72$

The z-score for X in company B's profit distribution is -0.72, which corresponds to the 23.58-th percentile.

8 0

3 years ago