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const2013 [10]
3 years ago
14

Can someone tell me how to solve quadratic equations by graphing ? like the steps

Mathematics
1 answer:
Arturiano [62]3 years ago
7 0

Answer:

another way of solving a quadratic equation is to solve it graphically. The roots of a quadratic equation are the x-intercepts of the graph. Graph the equation. This could either be done by making a table of values as we have done in previous sections or by computer or a graphing calculator

Step-by-step explanation:

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How to Solve 1.5 kg : 350kg
kondaur [170]

30/7

Step-by-step explanation:

1.5kg : 350g

1kg = 1000g

So, 1.5kg = 1500g

1500g : 350g

1500/350 = 30/7

The answer is 30/7.

6 0
2 years ago
The Toylot company makes an electric train with a motor that it claims will draw an average of only 0.8 ampere (A) under a norma
kotegsom [21]

Answer:

Test statistic = 3.1587

Step-by-step explanation:

We are given that the Toy-lot company makes an electric train with a motor that it claims will draw an average of only 0.8 ampere (A).

Also, a sample of eleven motors was tested, and it was found that the mean current was x = 1.20 A, with a sample standard deviation of s = 0.42 A.

So, Null Hypothesis, H_0 : \mu = 0.8 { claim of 0.8 A is not low}

Alternate Hypothesis, H_1 : \mu > 0.8 { claim of 0.8 A is too low}

Now, the test statistics used here will be;

           T.S. = \frac{Xbar - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 1.20 A

                 s = sample standard deviation = 0.42 A

                 n = sample size = 11 motors

So, Test statistics = \frac{1.20 - 0.8}{\frac{0.42}{\sqrt{11} } } ~ t_1_0

                             = 3.1587

At 1% level of significance, t table gives a critical value of 2.764 at 10 degree of freedom. Since our test statistics is higher than the critical value so we have sufficient evidence to reject null hypothesis .

Therefore, we conclude that Toy-lot claim of 0.8 A is too low.

8 0
4 years ago
This is easy for some ppl but not me
WINSTONCH [101]

Answer:

- 5  \frac{1}{3}  \div 3 \frac{1}{10}  \\  =  \frac{ - 5 \times 3 + 1}{3}  \div  \frac{3 \times 10 + 1}{10}  \\  =   \frac{ - 16}{3}  \times  \frac{10}{31}  \\  =  \frac{ - 160}{93}

Hope it will help :)

8 0
3 years ago
Read 2 more answers
The floor of the shallow end of a swimming pool is at -3 feet.The floor of the deep end is 9 feet deeper.What is the depth of th
Zepler [3.9K]
(-3) - 9 = -12 feet

I hope this helps, feel free to ask any questions you may have
4 0
4 years ago
Solve the following equation: <br><br> x^3 -168 = [24(x-2)] / 2<br><br> PLEASE REPLY ASAP
Nataly_w [17]
Hi Larry

x^3 - 168 = [ 24(x-2)] / 2
x^3 - 168 = (24x - 48)/2
x^3 - 168 = 12x - 24
Subtract 12x - 24 to both sides
x^3 - 168 - (12x - 24) = 12xx - 24 - (12x - 24)
x^3 - 12x - 144 = 0
Now, factor the left sides
(x - 6)(x^2 + 6x + 24) = 0
Set factors equal to 0
x - 6 = 0 or x^2 + 6x + 24 = 0
x = 0 + 6 or x^2 + 6x + 24 - 0
x = 6
Answer : X = 6

Good luck !
7 0
3 years ago
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