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Brut [27]
3 years ago
9

Evaluate C(n, n). A. 0 B. 1 C. n

Mathematics
1 answer:
horrorfan [7]3 years ago
4 0
C(n,n)=\dfrac{n!}{n!(n-n)!}=\dfrac1{0!}=\dfrac11=1

In other words, how many ways are there to choose n objects from a total of n objects? Just one; take all of them at the same time.
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B and C is the correct answer
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If the point (x, y) is on the small rectangle, then which point must be on the large rectangle?
ANTONII [103]
<h2>Explanation:</h2><h2></h2>

Hello! Remember you have to write complete questions in order to get good and exact answers. This question is incomplete but I'm going to help you assuming some things:

  • The small rectangle is built up by the x and y-axis and the point (x,y)=(6,4)

  • The large rectangle is built up by the x and y-axis and the point that follows the rule:

(x',y')\rightarrow (x+4,y+4)

For the small rectangle, the vertices are:

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Therefore, if (6,4) lies on the small rectangle, for the large rectangle we have:

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In conclusion:

If point (6,6) lies on the small rectangle, then (10,4) lies on the large rectangle.

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3 years ago
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Step-by-step explanation:

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