3 years ago

Evaluate C(n, n). A. 0 B. 1 C. n

1 answer:

4 0

$C(n,n)=\dfrac{n!}{n!(n-n)!}=\dfrac1{0!}=\dfrac11=1$

In other words, how many ways are there to choose $n$ objects from a total of $n$ objects? Just one; take all of them at the same time.

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fiasKO [112]

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1 year ago

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5 units is L'L ( I took the quiz and got it right)

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