So if you subtract the 0 out from the left side, the equation is now

. Since a x is common in both of the terms on the left side, you can factor it out, now making the equation look like

. When factoring, each of the separate things (x and (x-3)), must equal zero while the other one doesn't matter. So in order for the equation to be 0, the only potential options for x is 0 and 3. Therefore x=0 and x=3 are the two solutions
Answer:
×=30⁰ :)
Step-by-step explanation:
x⁰+(x+30⁰)= 90⁰
x⁰+x⁰= 90⁰-30⁰=60⁰
2x⁰=60⁰
60⁰÷2=30⁰ => x⁰=30⁰
verification:
30⁰+(30⁰+30⁰)=90⁰
Answer:
$69,250
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
it was right on edge