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vagabundo [1.1K]

3 years ago

6

Jacks average in math for the first nine weeks was an 88. His second nine weeks averange deceased to 81. What is the is the perc

ent of change from the first nine weeks to the second? Label increase or decrease

1 answer:

dolphi86 [110]3 years ago

5 0

It has to be decrease because from 88 to 81.

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Help !!! please show work so i know how to do it :)))

satela [25.4K]

Answer:

70

Step-by-step explanation:

the red lines mean the two sides are equal

so its an isosceles triangle meaning the two angles other than the 40° one are equal

the inner angles of a triangle must add up to 180

so 180-40 = 2x

140 = 2x

x = 140/2 = 70

6 0

2 years ago

Read 2 more answers

Which point would be a solution to the system of linear inequalities shown below? y>4 x-5\hspace{50px}y\ge\frac{3}{5} x-1 y&g

Sauron [17]

Answer:

$x < \frac{20}{17}$ and $y \ge \frac{-5}{17}$

Step-by-step explanation:

Given

$y>4 x-5\hspace{50px}y\ge\frac{3}{5} x-1$

Required

Find x and y

In the second equation. Assume that:

$y = \frac{3}{5}x - 1\\$

Substitute $y = \frac{3}{5}x - 1$ in the first equation

$y > 4x - 5$

$\frac{3}{5}x - 1 > 4x - 5$

Collect like terms

$\frac{3}{5}x - 4x > - 5 + 1$

$\frac{3}{5}x - 4x > -4$

Multiply through by 5

$3x - 20x > -20$

$-17x > -20$

Solve for x

$x < \frac{20}{17}$

Substitute this value of x in $y \ge \frac{3}{5}x - 1$

$y \ge \frac{3}{5}*\frac{20}{17} - 1$

$y \ge \frac{3}{1}*\frac{4}{17} - 1$

$y \ge \frac{12}{17} - 1$

$y \ge \frac{12- 17}{17}$

$y \ge \frac{-5}{17}$

3 0

3 years ago

The probability of winning a certain lottery is 1/77076 for people who play 908 times find the mean number of wins

Alex73 [517]

The mean is 0.0118 approximately. So option C is correct

<h3><u>Solution:</u></h3>

Given that , The probability of winning a certain lottery is $\frac{1}{77076}$ for people who play 908 times

We have to find the mean number of wins

$\text { The probability of winning a lottery }=\frac{1}{77076}$

Assume that a procedure yields a binomial distribution with a trial repeated n times.

Use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial.

$n=908, \text { probability } \mathrm{p}=\frac{1}{77076}$

$\text { Then, binomial mean }=n \times p$

$\begin{array}{l}{\mu=908 \times \frac{1}{77076}} \\\\ {\mu=\frac{908}{77076}} \\\\ {\mu=0.01178}\end{array}$

Hence, the mean is 0.0118 approximately. So option C is correct.

4 0

3 years ago

Which of the three equations have infinitely many solutions?

mina [271]

Answer:

I need to know the questions luv.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Which ordered pair is represented by the red point shown?

Leto [7]

The answer is (6,-4). By the way, this was very hard to read.

5 0

3 years ago