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FinnZ [79.3K]
3 years ago
12

Help please 1. Describe the transformations necessary to transform the graph of

Mathematics
1 answer:
natta225 [31]3 years ago
4 0

Here are all the steps, and what they do:

STEP 1: HORIZONTAL TRANSLATION

We transform

x^2\mapsto (x-1)^2

The general transformation is

f(x)\mapsto f(x+k)

These transformations translate the graph horizontally, k units to the left if k>0, k units to the right if k<0.

In this case, k = -1, so we translate the original graph 1 unit to the right.

STEP 2: VERTICAL STRETCH

We transform

(x-1)^2\mapsto 3(x-1)^2

The general transformation is

f(x)\mapsto kf(x)

These transformations stretch the graph vertically. The graph expands if |k|>1, while it shrinks if 0<|k|<1. If k is negative, we also reflect the graph with respect to the x axis.

In this case, k = 3, so we stretch the graph vertically by a factor 3.

STEP 3: VERTICAL TRANSLATION

We transform

3(x-1)^2\mapsto 3(x-1)^2+4

The general transformation is

f(x)\mapsto f(x)+k

These transformations translate the graph vertically, k units up if k>0, k units down if k<0.

In this case, k = 4, so we translate the graph 4 units up.

So, we start from the original graph of f(x)=x^2 and we:

  • Translate it 1 unit to the right
  • Stretch it vertically by a factor 3
  • Translate it 4 units up

(the order is important!)

to get the graph of g(x)=3(x-1)^2+4

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Can somebody help me on 23 and 24, it’s geometry
Luda [366]

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Step-by-step explanation:

As RS is the perpendicular bisector of DE, it will divide DE in two equal parts DS and SE

<u>Question number 23:</u>

Given

DS = 3x+10

SE = 6x-2

As the two segments are equal:

DS = SE\\3x+10 = 6x-2

Subtracting 10 from both sides

3x+10-10 = 6x-2-10\\3x = 6x-12

subtracting 6x from both sides

3x -6x = 6x-6x-12\\-3x = -12

Dividing both sides by -3

\frac{-3x}{-3} = \frac{-12}{-3}\\x = 4

Now

DS = 3x+10\\= 3(4)+10\\= 12+10\\=22

And

SE = 6x-2\\= 6(4)-2\\= 24 - 2\\=22\\DE = DS+SE\\= 22+22\\=44

<u>Question No 24:</u>

Given

DS = x+3

DE = 56

We know that:

DS = \frac{1}{2}DE\\x+3 = \frac{56}{2}\\x + 3 = 28\\x = 28-3\\x = 25

So

DS = 25+3 = 28

As DS is 28, SE will also be 28

Hence,

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Keywords: Bisector, Line segment

Learn more about line segments at:

  • brainly.com/question/629998
  • brainly.com/question/6208262

#LearnwithBrainly

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3 years ago
Help me please I just need math and that's all for math
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1. 3 1/4
2.9 1/2 hope it helped
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3 years ago
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Can someone help me please thank you
slavikrds [6]

Answer:

3j + 3m + 21

Step-by-step explanation:

Normally, they would each travel 3 miles, so the total would normally be 3j + 3m. However, for today, Jared ran another 21 miles, so 21 miles is added to the total.

Total distance = 3j + 3m + 21

3 0
3 years ago
Read 2 more answers
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