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FinnZ [79.3K]
3 years ago
12

Help please 1. Describe the transformations necessary to transform the graph of

Mathematics
1 answer:
natta225 [31]3 years ago
4 0

Here are all the steps, and what they do:

STEP 1: HORIZONTAL TRANSLATION

We transform

x^2\mapsto (x-1)^2

The general transformation is

f(x)\mapsto f(x+k)

These transformations translate the graph horizontally, k units to the left if k>0, k units to the right if k<0.

In this case, k = -1, so we translate the original graph 1 unit to the right.

STEP 2: VERTICAL STRETCH

We transform

(x-1)^2\mapsto 3(x-1)^2

The general transformation is

f(x)\mapsto kf(x)

These transformations stretch the graph vertically. The graph expands if |k|>1, while it shrinks if 0<|k|<1. If k is negative, we also reflect the graph with respect to the x axis.

In this case, k = 3, so we stretch the graph vertically by a factor 3.

STEP 3: VERTICAL TRANSLATION

We transform

3(x-1)^2\mapsto 3(x-1)^2+4

The general transformation is

f(x)\mapsto f(x)+k

These transformations translate the graph vertically, k units up if k>0, k units down if k<0.

In this case, k = 4, so we translate the graph 4 units up.

So, we start from the original graph of f(x)=x^2 and we:

  • Translate it 1 unit to the right
  • Stretch it vertically by a factor 3
  • Translate it 4 units up

(the order is important!)

to get the graph of g(x)=3(x-1)^2+4

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coldgirl [10]

Answer:

12

Step-by-step explanation:

Distribute the negative which would get your 3x + 6 -3x + 6. The 3x would cancel out and you would add 6+6 = 12

6 0
3 years ago
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Rodrigo bought a pumpkin pie for $4.85 and a can of whipped cream for $1.55. He gave the cashier $7.00. How much change should R
madam [21]
Answer:
$0.60

step-by-step explanation:
4.85 + 1.55 = 6.40
7.00 - 6.40 = 0.60
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2 years ago
Angle 3 is equal to angle
Phoenix [80]
Angle 3 is equal to angle 5 because of vertical angles.
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3 years ago
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At the same store, Peter bought 2 pairs of pants and 5 shirts for $61, and Jessica bought 3 pairs of pants and 4 shirts for $67.
svetlana [45]

Hey there!!

Given :

The total cost for 2 pairs of pants and 5 shirts is $61.

The total cost for 3 pairs of paints and 4 shirts is $67.

<em>Let's take the cost for each pair of paints as 'p' and the cost for each shirt as 's'. </em>

Now, let's get these into an equation.

<em>Peter's equation</em> :

... 2p + 5s = 61

<em>Jessica's equation : </em>

...3p + 4s = 67

......................................................................................................

2p + 5s = 61 --- (1)

3p + 4s = 67 --- (2)

Multiply the first equation with 3 and the second equation with 2.

6p + 15s = 183

6p + 8s = 134

S<em>ubtract both the equations - </em>

... 7s = 49

Divide both sides with 7.

... s = 7

<u><em>Hence, the cost of each shirt is $7. </em></u>

Hope my answer helps!!


6 0
3 years ago
Toxaphene is an insecticide that has been identified as a pollutant in the Great Lakes ecosystem. To investigate the effect of t
Likurg_2 [28]

Answer:

This data suggest that there is more variability in low-dose weight gains than in control weight gains.

Step-by-step explanation:

Let \sigma_{1}^{2} be the variance for the population of weight gains for rats given a low dose, and \sigma_{2}^{2} the variance for the population of weight gains for control rats whose diet did not include the insecticide.

We want to test H_{0}: \sigma_{1}^{2} = \sigma_{2}^{2} vs H_{1}: \sigma_{1}^{2} > \sigma_{2}^{2}. We have that the sample standard deviation for n_{2} = 22 female control rats was s_{2} = 28 g and for n_{1} = 18 female low-dose rats was s_{1} = 51 g. So, we have observed the value

F = \frac{s_{1}^{2}}{s_{2}^{2}} = \frac{(51)^{2}}{(28)^{2}} = 3.3176 which comes from a F distribution with n_{1} - 1 = 18 - 1 = 17 degrees of freedom (numerator) and n_{2} - 1 = 22 - 1 = 21 degrees of freedom (denominator).

As we want carry out a test of hypothesis at the significance level of 0.05, we should find the 95th quantile of the F distribution with 17 and 21 degrees of freedom, this value is 2.1389. The rejection region is given by {F > 2.1389}, because the observed value is 3.3176 > 2.1389, we reject the null hypothesis. So, this data suggest that there is more variability in low-dose weight gains than in control weight gains.

8 0
3 years ago
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