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3 years ago

Students in classes, displayed below, ate the same ratio of cheese pizza slices to pepperoni pizza slices.

Mathematics

1 answer:

Musya8 [376]3 years ago

4 0

Slices of cheese pizza slizes of pepperoni pizza total pizza
   2 5 7
   6    15 21
   8 20    28
   5 1/2 13 3/4 19 1/4
      3 1/3    8 1/3 11 2/3
   3/5    1 1/2 2 1/10

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The pool at "splash around" is open for 14 weeks during the summer. you can swim for $6 a session, or you can buy a membership f

Ratling [72]

Let

x--------> the number of sessions

y-------> the total payment

we know that

without membership:

$y=6x$ --------> equation $1$

with membership:

$y=100+4x$ --------> equation $2$

using a graph tool------> resolve the system of equations

see the attached figure

the solution is the point $(50,300)$

that means

For $x=50\ sessions$

the cost is $\$300$ in both forms

to justify buying the membership

$x > 50\ sessions$

therefore

<u>the answer is</u>

$x > 50\ sessions$

3 0

3 years ago

Read 2 more answers

A train leaves Philadelphia at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train t

polet [3.4K]

Answer: First train speed shall be 42 mi/hr

Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

(1) +s+=+42+

and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

8 0

3 years ago

Is 14,22,30 a Pythagorean triple

adell [148]

I don’t think soooooo

7 0

3 years ago

Read 2 more answers

Multiply.

Nady [450]

$\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}$

<h2>Explanation:</h2>

Here we have the following expression:

$3\sqrt{22}\sqrt{58}\sqrt{18}$

So we need to simplify that radical expression. By property of radicals we know that:

$\sqrt[n]{a}\sqrt[n]{b}=\sqrt[n]{ab}$

So:

$3\sqrt{22}\sqrt{58}\sqrt{18}=3\sqrt{22\times 58 \times 18}=3\sqrt{22968}$

The prime factorization of 22968 is:

$22968=2^3\cdot 3^2\cdot11\cdot 29$

Hence:

$3\sqrt{22968}=3\sqrt{2^3\cdot 3^2\cdot11\cdot 29}=3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29}$

By property:

$\sqrt[n]{a^n}=a$

So:

$3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29} \\ \\ 3(2)(3)\sqrt{2\cdot 11\cdot 29}=18\sqrt{638}$

Finally:

$\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}$

<h2>Learn more:</h2>

Radical expressions: brainly.com/question/13452541

#LearnWithBrainly

3 0

3 years ago

−8y ≥ 48

PilotLPTM [1.2K]

First divide both sides by -8. Remember when you divide by a negative for an inequality, you have to flip the inequality sign.

So the answer is:
y < or equal -6

6 0

3 years ago