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PIT_PIT [208]
4 years ago
12

How is the quotient 80,000 divided by 2,000 different from the quotient 80,000 divided by 200 or 80,000 divided by 20?

Mathematics
1 answer:
Mashcka [7]4 years ago
3 0
Notice that the divisors 2,000, 200 and 20 are similar except for the number of zeros.
You can remove a zero from each dividend equal to the number of zeros in the divisor.   
So 80,000 ÷ 2,000 is equivalent to 80 ÷ 2 = 40  ( I removed 3 zeros from each)
80,000 ÷ 200 is equivalent to 800 ÷ 2 = 400   (notice that I could only remove 2 zeros)
Finally 80,000 ÷ 20 only allows us to remove on zero ---    8,000 ÷ 2 = 4,000.
The smaller the divisor the greater the quotient (when dividing the same number - in this case  80,000)

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Solve for n. 4.5=0.5n.
N76 [4]
N=9

Since you are multiplying on the right side you have to divide when you bring 0.5 to the left side:
4.5 divided by 0.5 = n
9 = n
8 0
4 years ago
Read 2 more answers
the value of two numbers if their sum is 12 and their difference is 4. write a system of equation and find the two numbers
nikdorinn [45]

x+y=12

x-y=4

Then you solve:

x+y=12

 -y   -y

x=12-y

x-y=4

  +y  +y

x=4+y

4+y=12-y

  +y      +y

4+2y=12

-4        -4

2y=8

divide both sides by 2 to isolate y

y=4

Plug it into one of the equations

x+4=12

 -4    -4

x=8


6 0
3 years ago
A biologist is researching a newly discovered species of bacteria. At
lianna [129]

Answer:

  k ≈ 0.1733

Step-by-step explanation:

Using the numbers given, we find the multiplier of the population is 800/200 = 4 in 8 hours. This means the equation of growth can be written ...

  y = 200(4^(t/8))

When this is written in the form ...

  y = 200·e^(kt)

We can compare the two equations to see that ...

  4^(1/8) = e^k

Taking natural logarithms, we have ...

  1/8·ln(4) = k ≈ 0.1733

The growth rate k is approximately 0.1733.

_____

<em>Additional comment</em>

The comparison we were looking for was (4^(1/8))^t = (e^k)^t. Instead of "comparing" the equations, you could set them equal and solve for k.

  200(4^(t/8)) = 200e^(kt)

  4^(t/8) = e^(kt) . . . divide by 200

  t/8·ln(4) = kt·ln(e) . . . . take natural logs

  1/8·ln(4) = k . . . . . . use ln(e) = 1 and divide by t

6 0
3 years ago
−2x − 10y = 10 D: {−10, −5, 0, 5}<br><br> A. x=-10<br> B. x=-5<br> C. x=0<br> D. x=5
Vaselesa [24]

Answer:

the value of X Will be 0

hope like the answer

4 0
3 years ago
1: 9 - z +3 - 2z =<br> 2: n +5n=<br> 3: 12c - c=<br> 4: 9 - z + 3 - 2z
Taya2010 [7]

Answer:

1:12−3z

2:6n

3:11c

4: 12-3z

Step-by-step explanation:

1:

9 - z +3 - 2z

(9+3)+(−z−2z)

<u>12−3z </u>

2:

n +5n

<u>6n</u>

3:

12c - c

<u>11c</u>

4:

9 - z + 3 - 2z

(9+3)+(−z−2z)

<u>12-3z</u>

<u />

Hope this helped

6 0
3 years ago
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