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Eddi Din [679]
3 years ago
6

Solve for x. 16x – 3(4x + 5) = 2x + 9

Mathematics
2 answers:
aniked [119]3 years ago
8 0

Answer:

The answer is x=12

motikmotik3 years ago
7 0

To solve for x, you need to isolate/get the variable "x" by itself in the equation:

16x - 3(4x + 5) = 2x + 9          Distribute -3 into (4x + 5)

16x + (-3)4x + (-3)5 = 2x + 9

16x - 12x - 15 = 2x + 9         Combine like terms (terms that have the same variable and power/exponent), which are 16x - 12x, as they have the same variable "x" and a power/exponent of 1.

4x - 15 = 2x + 9        Subtract 2x on both sides

4x - 2x - 15 = 2x - 2x + 9

2x - 15 = 9     Add 15 on both sides

2x - 15 + 15 = 9 + 15

2x = 24          Divide 2 on both sides to get "x" by itself

\frac{2x}{2}=\frac{24}{2}

x = 12

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3 years ago
If the following system of equations was written as a matrix equation in the form AX = C,? and matrix A was expressed in the for
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The given equations are
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As a matrix equation,
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3 years ago
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Use an algebraic approach to solve the problem.
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Answer:

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

Step-by-step explanation:

Use the formula for the mean: sum of elements / number of elements

Let x represent her first exam score.

Her second exam score can be represented by x + 11, since it was 11 points better than her first.

Her third exam score can be represented by (x + 11) + 5, since it was 5 points better than her second.

Plug in all of these expressions into the mean formula. Plug in 87 as the mean, and plug in 3 as the number of elements (since there are 3 scores):

mean = sum of elements / number of elements

87 =  ( (x) + (x + 11) + (x + 11) + 5 ) / 3

Add like terms and solve for x:

87 = (3x + 27) / 3

261 = 3x + 27

234 = 3x

78 = x

So, her first score was a 78.

Find her second score by adding 11 to this:

78 + 11 = 89

Find her third score by adding 5 to the second score:

89 + 5 = 94

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

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