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krok68 [10]
3 years ago
14

In ΔNOP, the measure of ∠P=90°, PO = 48, NP = 55, and ON = 73. What is the value of the sine of ∠N to the nearest hundredth?

Mathematics
1 answer:
mojhsa [17]3 years ago
4 0

Answer:

0.66

Step-by-step explanation:

sin 90°/ 73 = sin <em>L</em><em> </em>N /48

=> sin <em>L</em><em> </em>N = 48×sin90° /73

= 48/73 = 0.66

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