3 years ago

In ΔNOP, the measure of ∠P=90°, PO = 48, NP = 55, and ON = 73. What is the value of the sine of ∠N to the nearest hundredth?

Mathematics

1 answer:

mojhsa [17]3 years ago

4 0

Answer:

0.66

Step-by-step explanation:

sin 90°/ 73 = sin L N /48

=> sin L N = 48×sin90° /73

= 48/73 = 0.66

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