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m_a_m_a [10]
3 years ago
13

What is the location of D on the decimal number line

Mathematics
1 answer:
natta225 [31]3 years ago
6 0

Answer:

need more information ?

Step-by-step explanation:

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Solve for x by first setting up two equations. Then find the PRODUCT of your solutions |2x+5|=7
Kobotan [32]

Answer: see below

Step-by-step explanation:

|2x+5|=7

2x+5=±7 ⇔ since the absolutely value of any number is all positive, so the value in side can be either positive or negative

2x+5=7  or  2x+5=-7

    2x=2            2x=-12

      x=1      or       x=-6

----------------------------------------

The product of the two solutions

1 × -6=-6

Hope this helps!! :)

Please let me know if you have any question

5 0
3 years ago
Write the ratio as a fraction in simplest form, with whole numbers in the numerator and denominator.
S_A_V [24]
The answer is 4/1 you just have to divide 7 from both numbers and then you will get 4/1
3 0
2 years ago
Read 2 more answers
Help me please I need your help in this question !?
den301095 [7]
14m+25= G
so, you would plug in how many months the membership would cost.
14(6)= 84
then add the additional fee to join which was $25

84+25= 109
7 0
3 years ago
Can a equation have more than one property present?
Feliz [49]

Answer:

yes it CAN have more than 1

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?
Trava [24]

Answer:

\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}

Step-by-step explanation:

The explicit formula for a geometric sequence:

a_n=a_1r^{n-1}

a_n - n-th term

a_1 - first term

r - common ratio

r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}

We have

a_1=-1,\ a_2=\dfrac{1}{4},\ a_3=-\dfrac{1}{6},\ ...

The common ratio:

r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}

<h2>It's not a geometric sequence.</h2>

If a_3=-\dfrac{1}{16} then the common ratio is r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}

Put to the explicit formula:

a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}

Put a_n=\dfrac{1}{1024} and solve for <em>n </em>:

-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1

\dfrac{1}{4^n}=\dfrac{1}{4^6}\iff n=6

5 0
3 years ago
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