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r-ruslan [8.4K]
2 years ago
10

Need help on this question

Mathematics
1 answer:
Aloiza [94]2 years ago
4 0
I hope this helps you

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Hello please help thanks i’ll give brainliest!
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Answer:

Step-by-step explanation:

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3 years ago
Which two parallelograms have the same area?
skad [1K]

Answer:

We can't answer the question cause we can't see all the shapes

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Test the claim that the mean GPA of night students is larger than 3.1 at the .10 significance level. The null and alternative hy
Alborosie

Answer:

H 0 : μ = 3.1    H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66

df = n-1=75-1 =74

The p value is:

p_v = P(t_{74} >8.66) =3.65x10^{-13}

The significance level is: 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1    H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

\bar X = 3.13 , s =0.03 , n =75

The statistic to check the hypothesis is given by:

t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}

Replacing the info given we got:

t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66

The degrees of freedom are given by:

df = n-1=75-1 =74

The p value since is a right tailed ted is given by:

p_v = P(t_{74} >8.66) =3.65x10^{-13}

The significance level is 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

6 0
3 years ago
-6h plus 4 - 3plus h equals 11
olga55 [171]

- 6h + 4 - 3 + h = 11
So we start by combining like terms;
- 6h + h =  - 5h
4 - 3 = 1
Now we have;
- 5h + 1 = 11
We then subtract 1 from both sides;
- 5h + 1 = 11
- 5h = 10
Then we divide both sides by 5;
- 5h = 10
- 5h \div  - 5h =  h
10 \div  - 5h =  - 2
Leaving the final answer to be h = -2
5 0
3 years ago
Make D the subject of S=D/T<br> You may use the flowchart to help you if you wish.
hammer [34]
Given the equation, S = D/T:

To make the D the subject of the equation, we can start by multiplying both sides by T to isolate D:

(T) S = D/T (T)

TS = D

Therefore, the final answer is D = TS
8 0
3 years ago
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