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masya89 [10]
3 years ago
13

PLEASE ANSWER I REALLY NEED IT ASAP (30points) ZOOM IN TO SEE IT BETTER

Mathematics
2 answers:
Alex3 years ago
7 0

Answer:

x=8     x=1

Step-by-step explanation:

f(x) = g(x)

6x^2 -5x +10 = 5x^2 +4x+2

Subtract 5x^2 from each side

6x^2-5x^2 -5x +10 = 5x^2-5x^2 +4x+2

x^2 -5x +10 = 4x+2

Subtract 4x from each side

x^2 -5x-4x +10 = 4x-4x+2

x^2 -9x +10 = 2

Subtract 2 from each side

x^2 -9x +10-2 = 2-2

x^2 -9x +8 =0

Factor

What 2 numbers multiply to 8 and add to -9

-8 *-1 = 8

-8-1 = -9

(x-8) (x-1) =0

Using the zero product property

x-8 = 0   x-1 =0

x=8     x=1

arsen [322]3 years ago
4 0

Answer:

x = 1 ; x = 8

Step-by-step explanation:

6x² - 5x + 10 = 5x² + 4x + 2

x² - 9x + 8 = 0

x² - 8x - x + 8 = 0

x(x - 8) - (x -8) = 0

(x - 8)(x - 1) = 0

x = 1, x = 8

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3 years ago
Can anyone help me on this? I need an exact answer please no guesses
Maksim231197 [3]

x = 32°

The triangle has 2 equal sides and is therefore isosceles, thus the 2 base angles are also congruent.

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x = \frac{180 - 116}{2} = \frac{64}{2} = 32



6 0
3 years ago
Read 2 more answers
Alan, Bill, and Calvin are playing a game with collectible cards. At the moment, Alan has 11 less than times the number of cards
Mama L [17]
<span> a=2.5b-11, c=1.5b+1, and a=c so

2.5b-11=1.5b+1

b=12 so a=19 and c=19

so a+b+c=50 </span>
8 0
3 years ago
Y+1=3(x-4)y+1=3(x−4) find the slope
julia-pushkina [17]

Answer:

0

y+1= (3x-12)y+1=3x-12

7 0
3 years ago
What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0
Tom [10]

Answer:

x=\frac{-7-\sqrt{5}}{2} or x=\frac{-7+ \sqrt{5}}{2}

Step-by-step explanation:

The given equation is

(2x+3)^2+8(2x+3)+11=0

Let us treat this as a quadratic equation in (2x+3).

where a=1,b=8,c=11

The solution is given by the quadratic formula;

(2x+3)=\frac{-b\pm \sqrt{b^2-4ac} }{2a}

We substitute these values into the formula to obtain;

(2x+3)=\frac{-8\pm \sqrt{8^2-4(1)(11)} }{2(1)}

(2x+3)=\frac{-8\pm \sqrt{64-44} }{2}

(2x+3)=\frac{-8\pm \sqrt{20} }{2}

(2x+3)=\frac{-8\pm2\sqrt{5} }{2}

(2x+3)=-4\pm \sqrt{5}

(2x+3)=-4-\sqrt{5} or (2x+3)=-4+ \sqrt{5}

2x=-3-4-\sqrt{5} or 2x=-3-4+ \sqrt{5}

2x=-7-\sqrt{5} or 2x=-7+ \sqrt{5}

x=\frac{-7-\sqrt{5}}{2} or x=\frac{-7+ \sqrt{5}}{2}

5 0
4 years ago
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