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3 years ago

Why is 4r + 5 = 3 not an algebraic expression?

1 answer:

6 0

4r + 5 = 3 is not an algebraic expression because expressions are basically equations but WITHOUT answers. In this equation, 3 is shown as the answer, which makes it an equation, not an expression.

Hope this helps! Please correct me if I'm wrong! :D

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4 years ago

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Write the function in <br> standard form?<br> f(x) = 5(x + 3)2 - 3

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3 years ago

The French club is sponsoring a bake sale.if their goal is to raise at least $140,how many pastries must they sell at $3.50 each

aleksklad [387]

"raise at least $140" tells you that, whatever the variables may be, the french club's profit needs to be 140 or more

they're selling pastries at $3.50 each, so we'll say that p is the number of pastries

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then just solve the inequality from there by isolating your variable:

140 >/= 3.50p

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3 years ago

Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

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3 years ago