Answer:
Additive inverse of (5-6) is (6-5),
------------------------------
So:
(5-6)+(6-5)=0
5-6+6-5=0
5-6=-6+5
-------------------------
Left <--- -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6 ---> Right
Move 5 places to the right of -6 and you should land on -1.
Answer:
-35
___
27
Step-by-step explanation:
Start by setting up your pairs (x,y)
-5 & 7 are x
3 & 9 are y
X * X
---------- ÷
Y * Y
(-5, 7)
---------
(3, 9)
-35
-------
27
Answer:
z score Perry 
z score Alice 
Alice had better year in comparison with Perry.
Step-by-step explanation:
Consider the provided information.
One year Perry had the lowest ERA of any male pitcher at his school, with an ERA of 3.02. For the males, the mean ERA was 4.206 and the standard deviation was 0.846.
To find z score use the formula.

Here μ=4.206 and σ=0.846



Alice had the lowest ERA of any female pitcher at the school with an ERA of 3.16. For the females, the mean ERA was 4.519 and the standard deviation was 0.789.
Find the z score
where μ=4.519 and σ=0.789



The Perry had an ERA with a z-score is –1.402. The Alice had an ERA with a z-score is –1.722.
It is clear that the z-score value for Perry is greater than the z-score value for Alice. This indicates that Alice had better year in comparison with Perry.
Answer:
16
Step-by-step explanation:
Dealing with a fraction exponent on hand can be converted by using the fractional exponents rule where the fraction exponent is converted to something like this:
![64^\frac{2}{3} = \sqrt[3]{64^{2}}\\](https://tex.z-dn.net/?f=64%5E%5Cfrac%7B2%7D%7B3%7D%20%3D%20%5Csqrt%5B3%5D%7B64%5E%7B2%7D%7D%5C%5C)
As you can see, the denominator of the fractional exponent is now the index of the radical. Here is a guide to know what goes where.
![64^\frac{x}{y} = \sqrt[y]{64^{x}}](https://tex.z-dn.net/?f=64%5E%5Cfrac%7Bx%7D%7By%7D%20%3D%20%5Csqrt%5By%5D%7B64%5E%7Bx%7D%7D)
Both the original problem (64^2/3) and the converted formula can be put into a calculator.
<u>Simplify (if you want to)</u>
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64 to the power of 2/3 is 16.
The answer is 2/1, I think. :)